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bixtya [17]
3 years ago
11

Water can keep engines operating at low temperatures. Which property of water most likely gives it this ability?

Chemistry
1 answer:
AVprozaik [17]3 years ago
6 0

Answer:

B: it has a high heat capacity

Explanation:

When any material has a high specific heat capacity/ heat capacity, it doesn't heat or cool very fast. So water can absorb more heat from the engine and can keep the engine cool or at low temperature for a longer period of time.

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Consider the reaction.
N76 [4]

Answer: m = 50 g ZnSO4

Explanation: First is convert the moles of Zn to the moles of ZnSO4 by having their mole ratio which is 2:2 based from the balanced equation. Next is convert the moles of ZnSO4 to mass using its molar mass.

0.311 mole Zn x 2 moles ZnSO4 / 2 moles Zn

= 0.311 moles ZnSO4

0.311 moles ZnSO4 x 161 g ZnSO4 / 1 mole ZnSO4

= 50 ZnSO4

5 0
3 years ago
Read 2 more answers
If the following elements were to combine with each other, choose which demonstrate the Law of Multiple Proportion. Select all t
Ilia_Sergeevich [38]

Missing question: Z:X = 7:1 A:Z = 2.5:1 A:Z = 2.2:1 Y:X = 11:1.

Answer is:<span> Z:X = 7:1 and Y:X = 11:1.
Law of multiple proportions or Dalton's Law said that the ratios of the masses of the second element which combine with a fixed mass of the first element will be ratios of small whole numbers. 
In this example ratios are whole numbers, A:Z = 2.5 : 1 and A:Z = 2.2 : 1 are not whole number ratios.</span>

3 0
3 years ago
35.0 mL of 12.0 M HCl is added to enough water to have a final volume of 1.20 L. What is the molarity of the final solution?
creativ13 [48]
<h3>Answer:</h3>

0.35 M

<h3>Explanation:</h3>

<u>We are given;</u>

  • Initial volume as 35.0 mL or 0.035 L
  • Initial molarity as 12.0 M
  • Final volume is 1.20 L

We are required to determine the final molarity of the solution;

  • Dilution involves adding solvent to a solution to make it more dilute which reduces the concentration and increases the solvent while maintaining solute constant.
  • Using dilution formula we can determine the final molarity.

M1V1 = M2V2

  • Rearranging the formula;

M2 = M1V1 ÷ V2

     = (12.0 M × 0.035 L) ÷ 1.2 L

      = 0.35 M

Thus, the final concentration of the solution is 0.35 M

6 0
3 years ago
When 20.0 grams of an unknown compound are dissolved in 500. grams of benzene, the freezing point of the resulting solution is 3
Lelu [443]

Answer: 120g/mol

Explanation:

The first step we are to take is to calculate the freezing point depression of the solution.

ΔT(f) = freezing point of pure solvent - freezing point of solution

ΔT(f) = 5.48 - 3.77

ΔT(f) = 1.71°C

Next we are to calculate the molal concentration of the solution using freezing point depression

ΔT(f) = K(f) * m

m = ΔT(f)/K(f)

m = 1.71/5.12

m = 0.333 molal

Now, we calculate the molecular weight of the unknown...

m = 0.333 mol = 0.333 mol X per kg of benzene

moles of X = 0.333 mol of X per kg of benzene * 0.5kg of benzene

moles of X = 0.1665

molecular weight of X = 20g of X/0.1665

molecular weight of X = 120/mol

5 0
3 years ago
How many nanoseconds are there in one minute?
umka21 [38]
1 minute equals 6e+10 nanoseconds.
I hope this helped! :>
3 0
3 years ago
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