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3 years ago

2. What's the kinetic energy of an object that has a mass of 12 kilograms and moves with a velocity of 10 m/s?

Chemistry

1 answer:

Dennis_Churaev [7]3 years ago

8 0

<h2>Let us solve for it </h2>

Explanation:

Energy

It is ability to do work .

There are so many forms of energy .

out of which mechanical energy is also one of the form .

Mechanical energy

It is the energy possessed by the body by virtue of its motion and state .

It is of two types :

Kinetic energy
Potential energy

Kinetic energy

It is the energy possessed by the body by virtue of its motion .

Its expression is :

K.E=1/2mv²

Here in above question it is given that :

mass = 2Kg

V=10m/sec

K.E will be = 1/2 x 2 x 10 x 10

K.E=100 J

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Lattice energy is an estimate bond of the bond:

lidiya [134]

Answer:

Strength

Explanation:

Lattice energy is the energy needed to remove one mole of ionic substance to its gaseous ion.

The lattice energy is used to determine the strength of a substance.

Lattice energy increases as the size of an ion decreases.
It decreases as the ion size increases.
This quantity is often determined using electrostatics method in the laboratory
The lattice energy is used to break an ionic solid to form a gaseous compound.

4 0

2 years ago

Read 2 more answers

Calculate the ph of a solution containing 0.0451 m potassium hydrogen tartrate and 0.028 m dipotassium tartrate. The ka values f

Marina86 [1]

Given buffer:

potassium hydrogen tartrate/dipotassium tartrate (KHC4H4O6/K2C4H4O6 )

[KHC4H4O6] = 0.0451 M

[K2C4H4O6] = 0.028 M

Ka1 = 9.2 *10^-4

Ka2 = 4.31*10^-5

Based on Henderson-Hasselbalch equation;

pH = pKa + log [conjugate base]/[acid]

where pka = -logKa

In this case we will use the ka corresponding to the deprotonation of the second proton i.e. ka2

pH = -log Ka2 + log [K2C4H4O6]/[KHC4H4O6]

= -log (4.31*10^-5) + log [0.0451]/[0.028]

pH = 4.15

4 0

3 years ago

Choose all the answers that apply. Which of the following will decrease reaction rate? increase pressure decrease temperature in

zavuch27 [327]

The following quantities will effect the reaction rate as follows:

1. On increasing Concentration of the reactant: Rate of the reaction will increases.

2. On increasing pressure : Increases the rate of reaction to the side where there are fewer number of molecules.

3.On increasing temperature of an endothermic reaction: Increases the rate of reaction

4. On decreasing temperature of an endothermic reaction: Increases the rate of reaction.

So the answer is increase pressure, decrease temperature, increase concentration will increases the rate of the reaction.

6 0

3 years ago

Read 2 more answers

6. A 25.0-mL sample of potassium chloride solution was found to have a mass of 25.225 g.

Morgarella [4.7K]

Answer:

6. a. 5.53 (m/m) %; b. 0.7490M

7. 0.156M

Explanation:

6. In the solution of KCl, there are 1.396g of KCl in 25.225g of solution. As mass/mass percent is:

Mass solute / Mass solution * 100

The mass/mass percent of KCl is:

a. 1.396g KCl / 25.225g solution * 100

5.53 (m/m) %

b. Molarity is moles of solute per liters of solution:

<em>Moles KCl -Molar mass: 74.55g/mol-:</em>

1.396g KCl * (1mol / 74.55g) = 0.018726 moles KCl

<em>Volume in liters: 25mL = 0.025L</em>

Molarity:

0.018726 moles KCl / 0.025L = 0.7490M

7. 0.90% means 0.90g of NaCl in 100g of solution:

<em>Moles NaCl -Molar mass: 58.44g/mol-:</em>

0.90g NaCl * (1mol / 58.44g) = 0.0154 moles NaCl

<em>Volume in Liters:</em>

100g * (1mL / 1.01g) = 99mL = 0.099L

Molarity:

0.0154 moles NaCl / 0.099L =

0.156M

4 0

2 years ago

What are some of the most common "chemicals" you use around your home on a daily basis? And what do you use those chemicals for?

elena55 [62]

Answer:

You use Bleach, Dimethyl Ammonium Chloride, Sodium Nitrite, Ethyl benzyl Ammonium Chloride, Lemon citrus, Baking soda, ETC

Explanation:

You use these in some of your cleaning supplies and home-made remedies.

5 0

3 years ago