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4 years ago

2. What's the kinetic energy of an object that has a mass of 12 kilograms and moves with a velocity of 10 m/s?

Chemistry

1 answer:

Dennis_Churaev [7]4 years ago

8 0

<h2>Let us solve for it </h2>

Explanation:

Energy

It is ability to do work .

There are so many forms of energy .

out of which mechanical energy is also one of the form .

Mechanical energy

It is the energy possessed by the body by virtue of its motion and state .

It is of two types :

Kinetic energy
Potential energy

Kinetic energy

It is the energy possessed by the body by virtue of its motion .

Its expression is :

K.E=1/2mv²

Here in above question it is given that :

mass = 2Kg

V=10m/sec

K.E will be = 1/2 x 2 x 10 x 10

K.E=100 J

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Round 0.02056 to three significant figures 0.0205 0.0206 0.021 0.020

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In this question we are asked to round off the figure 0.02056 to three significant figures.

We are given with four options to chose best out of four

a) 0.0205

b) 0.0206

c) 0.021

d) 0.020

In this question, option (b) is correct i.e. 0.0206.

There are four significant rules, we should keep in mind during round off:

Non-zero digits are so significant

Zeros between two non-zero digits are significant

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Trailing zeros are important only if the number contains a decimal point

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1 year ago

PLEASE HELP!!!!

LenKa [72]

Answer:

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3 years ago

At a certain temperature, the equilibrium constant, K c , for this reaction is 53.3. H 2 ( g ) + I 2 ( g ) − ⇀ ↽ − 2 HI ( g ) K

swat32

Answer:

$[HI]_{eq}=0.942M$

Explanation:

Hello,

In this case, the initial concentrations of hydrogen and iodine are the same:

$[H_2]_0=[I_2]_0=0.600M$

Thus, considering the given undergoing chemical reaction, one states the law of mass action in terms of the change $x$ due to the chemical change as shown below:

$Kc=\frac{(2x)^2}{(0.600M-x)(0.600M-x)}=53.3$

Therefore, solving for $x$ by quadratic equation one obtains:

$x_1=0.471M;x_2=0.826M$

Nevertheless, the feasible result is the first one as the second one results in negative concentrations, thus, the hydroiodic acid equilibrium concentration turns out:

$[HI]_{eq}=2*0.471M=0.942M$