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salantis [7]
3 years ago
6

How does an atom become an atom of another element is

Chemistry
1 answer:
ivann1987 [24]3 years ago
3 0
Can you give me the anwsers

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A flexible container at an initial volume of 3.10 L contains 9.51 mol of gas. More gas is then added to the container until it r
Schach [20]

Answer:

49.09 moles of gas are added to the container

Explanation:

Step 1: Data given

Initial volume = 3.10 L

Number of moles gas = 9.51 moles

The final volume = 19.1 L

The pressure, temperature remain constant

Step 2: Calculate number of moles gas

V1/n1 = V2/n2

⇒with V1 = the initial volume of the gas = 3.10 L

⇒with n1 = the initial number of moles = 9.51 moles

⇒with V2 = the increased volume = 19.1 L

⇒with n2 = the final number of moles gas

3.10L / 9.51 moles = 19.1 L / n2

n2 = 58.6 moles

The new number of moles is 58.6

Step 3: calculate the number of moles gas added

Δn = 58.6 - 9.51 = 49.09 moles

49.09 moles of gas are added to the container

7 0
3 years ago
What is baking soda chemically known as ? Excessive use of chemical
andreyandreev [35.5K]

Answer:

Baking Soda is NaHCO3 ---Sodium hydrogen Carbonate

Excessive use of Fertilizer can cause plants to develop shallow root systems,Decrease soil fertility and reduce Quality of Crops.

7 0
3 years ago
Read 2 more answers
In the preparation of a certain alkyl halide, 10 g of sodium bromide (NaBr), 10 mL distilled water (H20), and 9 mL 3-methyl-1-bu
Novosadov [1.4K]

Percentage yield shows the amount of reactants converted into products. The percentage yield of the reaction is 51.7%.

The equation of the reaction is sown in the image attached. The reaction is 1:1 as we can see.

Number of moles of NaBr = 10 g/103 g/mol = 0.097 moles

We can obtain the mass of 3-methyl-1-butanol from its density.

Mass = density × volume

Density of 3-methyl-1-butanol =  0.810 g/mL

Volume of  3-methyl-1-butanol = 9 mL

Mass of 3-methyl-1-butanol = 0.810 g/mL × 9 mL

Mass of 3-methyl-1-butanol = 7.29 g

Number of moles of 3-methyl-1-butanol =  mass/molar mass =  7.29 g/88 g/mol = 0.083 moles

Since the reaction is 1:1 then the limiting reagent is 3-methyl-1-butanol

Mass of product 1-bromo-3-methylbutane = number of moles × molar mass

Molar mass of 1-bromo-3-methylbutane = 151 g/mol

Mass of product 1-bromo-3-methylbutane = 0.083 moles × 151 g/mol

= 12.53 g

Recall that % yield = actual yield/theoretical yield × 100

Actual yield of product = 6.48 g

Theoretical yield = 12.53 g

% yield = 6.48 g/12.53 g × 100

% yield = 51.7%

Learn more: brainly.com/question/5325004

7 0
2 years ago
How would the addition of protons affect the concentration of CH3COOH? How would the addition of OH– affect the amount of CH3COO
Deffense [45]

Answer:

1) increase concentration

2) decrease the amount

3) decrease the concentration

4) it would increase

Explanation: edge 2021

8 0
3 years ago
Read 2 more answers
What is metaphase <br> HELEPWOAUSJSKQJDHEHR
IrinaVladis [17]

Answer:

the second stage of cell division. its between prophase and anaphase during the chromosomes become attached to spindle fibers.

5 0
2 years ago
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