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4 years ago

6

How does an atom become an atom of another element is

1 answer:

ivann1987 [24]4 years ago

3 0

Can you give me the anwsers

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"The difference in our frame of reference between schools of wild Blue Fin Tuna and wild populations of many types of "land base

KengaRu [80]

Answer:

1. Wildlife

2. Seafood

Explanation:

1. Wildlife refers to the species which are not domesticated by the humans and they live as a wild organisms in the areas which are not interfered with the humans. In the given question, the wild creatures that live on the land therefore are considered a part of the wildlife.

2. Seafood refers to the species which are considered as food which humans get from the sea. In the given question, the Blue Fin fishes are considered a seafood therefore.

7 0

3 years ago

Why is it important to predict consequences when decision-making?

zavuch27 [327]

The correct answer is b

3 0

3 years ago

Determine the value of the equilibrium constant, Kgoal, for the reactionN2(g)+H2O(g)⇌NO(g)+12N2H4(g), Kgoal=?by making use of th

Black_prince [1.1K]

Answer:

$K_{goal}=1.793*10^{-33}$

Explanation:

N2(g)+O2(g)⇌2NO(g), $K_1 = 4.10*10^{-31}$

N2(g)+2H2(g)⇌N2H4(g), $K_2 = 7.40*10^{-26}$

2H2O(g)⇌2H2(g)+O2(g), $K_3 = 1.06*10^{-10}$

If we add above reaction we will get:

2N2(g)+2H2O(g)⇌2NO(g)+N2H4(g) Eq (1)

Equilibrium constant for Eq (1) is $K_1*K_3*K_3$

Divide Eq (1) by 2, it will become:

N2(g)+H2O(g)⇌NO(g)+1/2N2H4(g) Eq (2)

Equilibrium constant for Eq (2) is $(K_1*K_3*K_3)^{1/2}$

$Equilibrium constant =K_{goal}= (K_1*K_2*K_3)^{1/2}\\K_{goal}= (4.10*10^{-31} *7.40*10^{-26}*1.06*10^{-10})^{1/2}\\K_{goal}=1.793*10^{-33}$

7 0

4 years ago

A certain compound has the percent composition (by mass) 85.63% C and 14.37% H. The molar mass of the compound is 42.0 g/mol. Ca

AlekseyPX

Answer:

The molecular formula is C3H6

Explanation:

Step 1: Data given

Suppose the compound has a mass of 100 grams

The compound contains:

85.63 % C = 85.63 grams C

14.37 % H = 14.37 grams H

Molar mass C = 12.01 g/mol

Molar mass H = 1.01 g/mol

Step 2: Calculate moles

Moles = grams / molar mass

Moles C = 85.63 grams / 12.01 g/mol

Moles C = 7.130 moles

Moles H = 14.37 grams / 1.01 g/mol

Moles H = 14.2 moles

Step 3: Calculate the mol ratio

We divide by the smallest amount of moles

C: 7.130 moles / 7.130 moles = 1

H = 14.2 moles / 7.130 moles = 2

The empirical formula is CH2

The molar mass of CH2 = 14 g/mol

Step 4: Calculate molecular formula

We have to multiply the empirical formula by n

n = 42 / 14 = 3

n*(CH2) = C3H6

The molecular formula is C3H6

8 0

3 years ago

Question 6(Multiple Choice Worth 2 points)

Rina8888 [55]

4.2 × 10²² atoms Al × (1 mol Al / 6.022 × 10²³) = moles Al

Last one: fraction 1 mole Al over 6.022 × 10²³ atoms Al

8 0

3 years ago