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Nonamiya [84]
3 years ago
11

Someone please help me sort these out for either if they are Heterogenous, solution, suspension, or colloid. Tuna casserole, gre

en salad, gelatin dessert, apple juice, oil and vinegar salad dressing, and chocolate chip cookies
Chemistry
1 answer:
Sphinxa [80]3 years ago
7 0
Heterogeneous-a mixture of two or more things
solution-a substance that dissolves
suspension-mixture where solid particles do not dissolve
colloid-does not settle and cannot be seperated

Heterogeneous
- tuna casserole
-chocolate chip cookies
-gelatin dessert
-green salad
Solution
-oil (?) depends 
Suspension
-vinegar salad dressing
-oil (?) it could go in either catagory
Colloid
-vinegar salad dressing
-oil (?)

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Write both answers to at least two decimal places. Calculate the pH of a 0.160 M solution of KOH.Part 2 (1 point) Calculate the
Evgen [1.6K]

To calculate the pH of a solution, we first need to find the concentration of hydronium ions in the solution. Since KOH is a strong base, it dissociates completely in water to produce hydroxide ions (OH-) and potassium ions (K+).

The concentration of hydronium ions in a solution of KOH can be calculated using the concentration of hydroxide ions and the equilibrium constant for water, which is equal to 1.00 x 10^-14 at 25 degrees Celsius.

The concentration of hydroxide ions in a 0.160 M solution of KOH is equal to the concentration of KOH, which is 0.160 M. The concentration of hydronium ions in the solution can be calculated using the equation below:

[H3O+] = (1.00 x 10^-14) / [OH-]

Substituting the concentration of hydroxide ions into the equation above, we get:

[H3O+] = (1.00 x 10^-14) / (0.160 M) = 6.25 x 10^-13 M

To calculate the pH of the solution, we need to take the negative logarithm of the concentration of hydronium ions. This can be done using the equation below:

pH = -log([H3O+])

Substituting the concentration of hydronium ions into the equation above, we get:

pH = -log(6.25 x 10^-13) = 12.20

The pH of a 0.160 M solution of KOH is 12.20.

To calculate the pOH of a solution, we first need to find the concentration of hydroxide ions in the solution. Since we already calculated this value above, we can simply use the concentration of hydroxide ions we found earlier: 0.160 M.

To calculate the pOH of the solution, we need to take the negative logarithm of the concentration of hydroxide ions. This can be done using the equation below:

pOH = -log([OH-])

Substituting the concentration of hydroxide ions into the equation above, we get:

pOH = -log(0.160 M) = 1.80

The pOH of a 0.160 M solution of KOH is 1.80.

Learn more about pH:
brainly.com/question/28864035

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7 0
1 year ago
With the levels closest to the nucleus of
Dmitry_Shevchenko [17]

Answer:

The first energy level is closest to the nucleus. The second energy level is a little farther away than the first. ... The electrons in the energy level farthest from the nucleus are called valence electrons. Atoms in the same column (group) in the periodic table have the same number of valence electrons.

Explanation:

5 0
3 years ago
Which of the following has the smallest radius? <br> A. O^2- <br> B. F^- <br> C. Li^- <br> D. Be^2+
nordsb [41]

Answer : The correct option is, (D) Be^{2+}

Explanation :

Effective nuclear charge : It is defined as the attraction of the protons present in the nucleus of an atom to the outermost electrons.

For ions, the effective nuclear charge changes than the neutral atom.

There are two types of ions:

Cations: They are formed when an atom looses its valence electrons. They are positive ions.

Anions: They are formed when an atom gain electrons in its outermost shell. They are negative ions.

For positive ions, the removal of electron increases the nuclear charge for an outermost electron because the outermost electrons are more strongly attracted by the nucleus. Thus, the effective nuclear charge increases for cations.

From this we conclude that, the size of the cation is smaller than their neutral atom because it has less number of electrons while its nuclear charge remains the same. So, the nucleus attracts the electron more towards itself and leads to the decrease in size.

For negative ions, the addition of electron decreases the nuclear charge for an outermost electron because the outermost electrons are less strongly attracted by the nucleus. Thus, the effective nuclear charge decreases for anions.

From this we conclude that, the size of the anion is greater than their neutral atom because it has more number of electrons while its nuclear charge remains the same. So, the nucleus attracts the electron less towards itself and leads to the increase in size.

Thus, the increasing order of radius of ions will be:

Be^{2+}

Hence, the smallest radius of ion is, Be^{2+}

4 0
3 years ago
Please help me with all 3! Thank You!!
julsineya [31]
The first is Design Process, the second is To see if the design solves the problem
5 0
3 years ago
g What is the half-life for a particular reaction if the rate law is rate = (1291 M⁻¹*min⁻¹)[A]² and the initial concentration o
Gnoma [55]

Answer:

t_{1/2}=3.10x10^{-3}min=0.186s

Explanation:

Hello,

In this case, for the calculation of the half-life for the mentioned reaction we first must realize that considering the units of the rate constant and the form of the rate law, it is a second-order reaction, therefore, the half-life expression is:

t_{1/2}=\frac{1}{k[A]_0}

Therefore, we obtain:

t_{1/2}=\frac{1}{1291\frac{1}{M*min}*0.250M}\\\\t_{1/2}=3.10x10^{-3}min=0.186s

Regards.

4 0
3 years ago
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