Explanation:
It is given that,
Mass of the box, m = 10 kg
Force with which the box is pulled, F = 50 N
It is moved a distance of 4 m
Force of friction acting on the box, f = 20 N
We need to find the initial kinetic energy the box have. It is clear that the box is at rest initially. As there is no motion in the box at that time. The formula for the kinetic energy of the box is given by :
As v = 0
So, the initial kinetic energy of the box is 0. Hence, this is the required solution.
Answer:
They are all a cycle!
Explanation:
They just are all cycles.
Answer:
Explanation:
The magnetic field can be find using the equation
You can cancel a element of v'
Solve to magnetic field
The charge and mass of the proton are:
,
Replacing numeric
It is in the noble gas group which has a full valence electron shell found in group 18
Answer:
a) 21.6 KN/m
b)v = 18.56 m/s
Explanation:
For this problem, the spring should be strong enough to get the car just over the top so:
mgh = (1/2)kx^2
(400)*(9.8)*(10) = (0.5)*(k)*(2.0^2)
k = 39200/2.645
k = 19600 N/m
a) K increased by Increase by 10%, so:
k = 19600 * 1.10 = 21560 N/m = 21.6KN/m---->specified spring constant
b) Now, Maximum speed of a 350 kg car will be at the bottom of the roller coaster:
therefore, (1/2)mv^2 + mg(Y_1-Y_2) = (1/2)kx^2
(0.5)*(350)*(v^2) + (350)(9.8)(10-15) =(0.5)*(21560)*(2.0^2)
v^2 = 344.4
v = 18.56 m/s