Radium........ Hope this helps :)
Given k=100, Area if plate A = 1.00 cm2

Thickness of rutile 

Without any dielectric medium capacitance of a parallel plate capacitor is c = oAd
When a dielectric is placed between capacitors plates then capacitance c1 = KoAd
Here
, 
Now 



Correct Option: A
What purposes serve parallel plate capacitors?
The following are some uses for parallel plate capacitors:
- This kind of capacitor is utilized in rechargeable energy systems such as batteries.
- These capacitors are used in systems for dynamic digital memory.
- Such capacitors are used in pulsed laser and radar circuits.
To learn more about Parallel plate capacitors, visit:
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PE=mgh=150kg*9.8m/c² *50m=73500 J
W=F*d=mgd = 2.5*9.8*3.0 = 73.7J
W=mgh=68.0*7.62*9.8 =50.78 J
150 lb = 68.0 kg
25 ft = 7.62m
Explanation:
The distance that a car travels down the interstate can be calculated with the following formula:
Distance = Speed x Time
(A) Speed of the car, v = 70 miles per hour = 31.29 m/s
Time, d = 6 hours = 21600 s
Distance = Speed x Time
D = 31.29 m/s × 21600 s
D = 675864 meters
or

(b) Time, d = 10 hours = 36000 s
Distance = Speed x Time
D = 31.29 m/s × 36000 s
D = 1126440 meters
or

(c) Time, d = 15 hours = 54000 s
Distance = Speed x Time
D = 31.29 m/s × 54000 s
D = 1689660 meters
or

Hence, this is the required solution.
Answer:
72.324 J
Explanation:
Formula for gravitational potential energy is given by;
GPE = mgh.
Where;
m = mass
g = acceleration due to gravity
h = height
We are given;
m = 4.1 kg
h = 1.8 m
Thus;
GPE = 4.1 × 9.8 × 1.8 = 72.324 J