Electric Forces. ... Just like objects that have mass exert gravitational forces on each other, objects that are charged will also exert electric forces on each other. The electric force is directly proportional to the charge of the two objects and inversely proportional to the distance between them squared.
Answer:
6.88 mA
Explanation:
Given:
Resistance, R = 594 Ω
Capacitance = 1.3 μF
emf, V = 6.53 V
Time, t = 1 time constant
Now,
The initial current, I₀ = 
or
I₀ = 
or
I₀ = 0.0109 A
also,
I = ![I_0[1-e^{-\frac{t}{\tau}}]](https://tex.z-dn.net/?f=I_0%5B1-e%5E%7B-%5Cfrac%7Bt%7D%7B%5Ctau%7D%7D%5D)
here,
τ = time constant
e = 2.717
on substituting the respective values, we get
I = ![0.0109[1-e^{-\frac{\tau}{\tau}}]](https://tex.z-dn.net/?f=0.0109%5B1-e%5E%7B-%5Cfrac%7B%5Ctau%7D%7B%5Ctau%7D%7D%5D)
or
I =
or
I = 0.00688 A
or
I = 6.88 mA
Hope this helps!!!!!!!!!!!!!
Answer:
like horror? or action haha
Explanation:
Answer:
Explanation:
a ) Direction of the magnetic field will be in positive x direction.
The direction of the vector E X B gives the direction of motion of wave.
b ) Magnitude of magnetic field is given by the relation
E₀ / B₀ = c , c is velocity of light
B₀ = E₀ / c
= 20 / (3 x 10⁸)
= 6.67 x 10⁻⁸ T
c ) Average power flowing per unit area by this wave is called Poynting vector
c ε₀E₀² , ε₀ = 8.85X10⁻¹²
= 3 X 10⁸ X 8.85 X 10⁻¹² X 20²
= 1.062 W m⁻²