This is just testing your ability to recall that kinetic energy is given by:
<span>k.e. = ½mv² </span>
<span>where m is the mass and v is the velocity of the particle. </span>
<span>The frequency of the light is redundant information. </span>
<span>Here, you are given m = 9.1 * 10^-31 kg and v = 7.00 * 10^5 m/s. </span>
<span>Just plug in the values: </span>
<span>k.e. = ½ * 9.1 * 10^-31 * (7.00 * 10^5)² </span>
<span>k.e. = 2.23 * 10^-19 J
so it will be d:2.2*10^-19 J</span>
This is the period in a simple harmonic motion which is 2 seconds in this question.
<h3>
What is Period ?</h3>
The period of an oscillatory object can be defined as the total time taken by a vibrating body to make one complete revolution about a reference point.
We are given the below question
2×3.14√(1.0m/(9.8〖ms〗^(2) )= T
This question can as well be expressed as
2π√(L/g) which is equal to period T.
In a nut shell, Period T = 2×3.14√(1.0m/9.8)
T = 6.28√0.102
T = 6.28 × 0.32
T = 2.006 s
Therefore, the period T of the oscillation is 2 seconds approximately.
Learn more about Period here: brainly.com/question/12588483
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Answer:
Neutrons and protons are located in the nucleus of the atom.
Explanation:
And electrons are in the electron cloud.