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3 years ago

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The periodic table is useful because it is organized to show many patterns and trends. What property shows a decrease moving fro

m the bottom of Group 3 to the top of Group 3?

1 answer:

Morgarella [4.7K]3 years ago

3 0

Answer:

"Electronegativity" decrease moving from the bottom of Group 3 to the top of Group 3

Explanation:

Electronegativity of an element tell us about the ability of an atom to attract the electrons towards the atom. It depends upon the atomic number and also the distance between the valence electrons that is present in the charged nucleus. The electronegativity will increase from left to right while moving in the periodic table. Electronegativity decreases from bottom to top. To measure the electronegativity pauling scale is used.

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The production of ammonia (NH3) under standard conditions at 25°C is represented by the following thermochemical equation. N2(g)

asambeis [7]

Answer:

44,901 kilo Joule heat is released when $1.663\times 10^4 g$ grams of ammonia is produced.

Explanation:

Moles of ammonia gas produced :

$\frac{1.663\times 10^4 g}{17 g/mol}=978.235 mol$

According to reaction, when 2 moles of ammonia are produced 9.18 kilo joules of energy is also released.

So, When 978.235 moles of ammonia gas is produced the energy released will be:

$\frac{-91.8 kJ}{2}\times 978.235 mol=-44,900.98 kJ\approx -44,901 kJ$

(negative sign indicates that energy is released as heat)

44,901 kilo Joule heat is released when $1.663\times 10^4 g$ grams of ammonia is produced.

7 0

3 years ago

inn [45]

Answer:

PART A 1st order in A and 0th order in B

Part B The reaction rate increases

Explanation:

<u>PART A </u>

The rate law of the arbitrary chemical reaction is given by

$-r_A=k\times\left[A\right]^\alpha\times\left[B\right]^\beta\bigm$

Replacing for the data

Expression 1 $0.00639=k\times{0.12}^\alpha\times{0.22}^\beta$

Expression 2 $0.01280=k\times{0.24}^\alpha\times{0.22}^\beta$

Expression 3 $0.00639=k\times{0.12}^\alpha\times{0.11}^\beta$

Making the quotient between the fist two expressions

$\frac{0.00639}{0.01280}=\left(\frac{0.12}{0.24}\right)^\alpha$

Then the expression for $\alpha$

$\alpha=\frac{ln\frac{0.00639}{0.01280}}{ln\frac{0.12}{0.24}}=1\bigm$

Doing the same between the expressions 1 and 3

$\frac{0.00639}{0.00639}=\left(\frac{0.22}{0.11}\right)^\beta$

Then

$\beta=\frac{ln\frac{0.00639}{0.00639}}{ln\frac{0.22}{0.11}}=0\bigm$

This means that the reaction is 1st order respect to A and 0th order respect to B .

<u>PART B </u>

By the molecular kinetics theory, if an increment in the temperature occurs, the molecules will have greater kinetic energy and, consequently, will move faster. Thus, the possibility of colliding with another molecule increases. These collisions are necessary for the reaction. Therefore, an increase in temperature necessarily produces an increase in the reaction rate.

4 0

3 years ago

ZILLDIFFEQMODAP11 3.1.021. My Notes Ask Your Teacher A tank contains 150 liters of fluid in which 10 grams of salt is dissolved.

SSSSS [86.1K]

Answer:

Therefore, the number of grams of salt in the tank at time t is $A(t) = 150-140 e^{-\frac{t}{30} }$

Explanation:

Given:

Tank A contain $V_{1} = 150$ lit

Rate $\alpha = 5 \frac{L}{min}$

Dissolved salt $A = 10$ gm

Salt pumped in one minute is $4 \frac{L}{min}$

Salt pumped out is $\frac{5L}{150L} = \frac{1}{30}$ of initial amount added salt.

To find $A(t)$

$\frac{dA}{dt} = Rate _{in} - Rate _{out}$

$A' = 5 - \frac{A}{30}$

$A' + \frac{A}{30} = 5$

Solving above equation,

$I .F = e^{\int\limits {p} \, dt }$

$y = e^{\int\limits {\frac{1}{30} } \, dt }$

$y = e^{\frac{t}{30} }$

$(Ae^{\frac{t}{30} } )' = 5 e^{\frac{t}{30} } + c$

Integrating on both side,

$Ae^{\frac{t}{30} } = 5 \times 30 e^{\frac{t}{30} } +c$

Add $e^{-\frac{t}{30} }$ on above equation,

$A = 150 + ce^{-\frac{t}{30} }$

Here given in question, $A(t=0) = 10$

$10 =150 +c$

$c = -140$

Put value of constant in above equation, and find the number of grams of salt in the tank at time t.

$A(t) = 150-140 e^{-\frac{t}{30} }$

Therefore, the number of grams of salt in the tank at time t is $A(t) = 150-140 e^{-\frac{t}{30} }$

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3 years ago

1. Metals are found on the <br> left or right side of the periodic table?

Inessa [10]

At the left side if it is nonmetal then upper right

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3 years ago

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There are 81 amino acid residues in the precursor molecule of bovine insulin. What is the least number of bases that must be in

Usimov [2.4K]

If you count the methionine expressed for the start codon as part of the precursor protein, then (81+1)*3. (The start codon is expressed, but the stop codon isn't.)

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4 years ago

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