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2 years ago

When calcium and chlorine react to form calcium chloride, which substance is reduced? *

Chemistry

2 answers:

zhannawk [14.2K]2 years ago

6 0

Answer:-

When the reaction takes place Ca is reduced or is an oxidizing agent.

Reaction:

Ca + 2Cl =CaCl2

Note: There is a +2 charge on Ca(Calcium) and -1 charge on each Cl-atom(Chlorine atom) hence the charges are cancelled. Therefore, the total charge on the whole compound is zero.

Explanation:-

• Reduction: gain of electron/electrons

gain of hydrogen

loss of oxygen

Oxidation: gain of oxygen

loss of hydrogen

loss of electron/electrons.

• Oxidizing agent/reduced

Reducing agent/oxidized

• The molecule that is oxidized loses an electron and the molecule that is reduced gains the electron that was lost by the oxidized molecule.

MAVERICK [17]2 years ago

6 0

Answer:

$\boxed{\text{Chlorine}}$

Explanation:

We must use oxidation numbers to decide which substance is reduced.

$\rm \stackrel{\hbox{0}}{\hbox{Ca}} + \stackrel{\hbox{0}}{\hbox{ Cl}_{2} }\longrightarrow \stackrel{\hbox{+2}}{\hbox{Ca }}\stackrel{\hbox{-1}}{\hbox{Cl}_{2}}$

The oxidation number of Ca increases from 0 in Ca to +2 in CaCl₂.

The oxidation number of Cl decreases from 0 in Cl₂ to -1 in CaCl₂.

$\text{A decrease in oxidation number is reduction, so } \boxed{\textbf{Cl$_{2}$ is the substance reduced.}}$

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Answer:

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2 years ago

Explain how the cell membrane controls the movement of materials into and out of the cell ?

sukhopar [10]

It's called simple diffusion, the small molecules without charges such as oxygen and carbon dioxide can flow through a plasma membrane without assistance and without expending energy. Other substances such as proteins, glucose and charged particles called ions cannot pass through the selectively permeable membrane.

5 0

2 years ago

1. Stirring increases the rate of solution

Blababa [14]

Answer:

1) The correct answer is A. Collision

2) A hot solvent helps a solid dissolve faster because an increase in kinetic energy that also increases the rate of collisions

Explanation:

When a solute is added into a solvent and stirred, the solute particles get distributed to all parts of the solvent as a result of stirring.

More collisions occur between the solute and the solvent due to stirring. This increases the rate of dissolving.

When a solvent is heated, then the kinetic energy would increase and the atoms will collide with a much greater force. As a result, ore solute will be able to dissolve in the solvent.

3 0

2 years ago

If 2.68 g of benzaldehyde are involved with the mixed aldol condensation reaction, how many moles of benzaldehyde are present? R

Zielflug [23.3K]

Answer:

The number of moles of benzaldehyde = 0.0253 moles

Explanation:

The molecular formula of benzaldehyde is C₇H₆O

Its molecular mass is calculated from the atomic masses of the constituent atoms.

C = 12.0 g: H = 1.0 g; O = 16.0 g

Molecular mass = ( 12 * 7) + (1 * 6) + (16 * 1) = 106.0 g/mol

Number of moles of substance = mass of substance/ molar mass of the substance

mass of benzaldehyde = 2.68; molar mass = 106.0 g/mol

Number of moles of benzaldehyde = 2.68 g/ 106 g/mol = 0.0253 moles

Therefore, the number of moles of benzaldehyde = 0.0253 moles

8 0

2 years ago

The dissolution of 0.200 l of sulfur dioxide at 19 °c and 745 mmhg in water yields 500.0 ml of aqueous sulfurous acid. The solut

aivan3 [116]

Answer:

$Molarity=1.22\ M$

Explanation:

Given:

Pressure = 745 mm Hg

Also, P (mm Hg) = P (atm) / 760

Pressure = 745 / 760 = 0.9803 atm

Temperature = 19 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (19 + 273.15) K = 292.15 K

Volume = 0.200 L

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9803 atm × 0.200 L = n × 0.0821 L.atm/K.mol × 292.15 K

⇒n = 0.008174 moles

From the reaction shown below:-

$H_2SO_3+2NaOH\rightarrow Na_2SO_3+2H_2O$

1 mole of $H_2SO_4$ react with 2 moles of $NaOH$

0.008174 mole of $H_2SO_4$ react with 2*0.008174 moles of $NaOH$

Moles of $NaOH$ = 0.016348 moles

Volume = 13.4 mL = 0.0134 L ( 1 mL = 0.001 L)

So,

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity=\frac{0.016348}{0.0134}\ M$

$Molarity=1.22\ M$

8 0

2 years ago