If that statement were true, then you would never have any reason to eat.
It might taste good for a while, but it would never help you stand up and
move around.
Where WOULD you get the energy to stand up and walk, if it didn't
come from food ? ?
The whole idea is pretty absurd. I guess the statement is not true.
Answer:
A picture of a baseball being thrown tworad a batter at home plate.
To solve this problem we will start by defining the length of the shortest stick as 'x'. And the magnitude of the longest stick, according to the statement as
![x+2.93](https://tex.z-dn.net/?f=x%2B2.93)
Both cover a magnitude of 8.32 ft, therefore
![x +(x+2.97) = 8.32](https://tex.z-dn.net/?f=x%20%2B%28x%2B2.97%29%20%3D%208.32)
Now solving for x we have,
![x + (x + 2.93) = 8.32](https://tex.z-dn.net/?f=x%20%2B%20%28x%20%2B%202.93%29%20%3D%208.32)
![2x + 2.93 = 8.32](https://tex.z-dn.net/?f=2x%20%2B%202.93%20%3D%208.32)
![2x = 8.32 - 2.93](https://tex.z-dn.net/?f=2x%20%3D%208.32%20-%202.93)
![x = \frac{ 8.32 - 2.93}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B%208.32%20-%202.93%7D%7B2%7D)
![x = 2.695 ft](https://tex.z-dn.net/?f=x%20%3D%202.695%20ft)
Therefore the shorter stick is 2.695ft long.
Answer:
(a). The path length is 3.09 m at 30°.
(b). The path length is 188.4 m at 30 rad.
(c). The path length is 1111.5 m at 30 rev.
Explanation:
Given that,
Radius = 5.9 m
(a). Angle ![\theta=30°](https://tex.z-dn.net/?f=%5Ctheta%3D30%C2%B0)
We need to calculate the angle in radian
![\theta=30\times\dfrac{\pi}{180}](https://tex.z-dn.net/?f=%5Ctheta%3D30%5Ctimes%5Cdfrac%7B%5Cpi%7D%7B180%7D)
We need to calculate the path length
Using formula of path length
![Path\ length =angle\times radius](https://tex.z-dn.net/?f=Path%5C%20length%20%3Dangle%5Ctimes%20radius)
![Path\ length=0.523\times5.9](https://tex.z-dn.net/?f=Path%5C%20length%3D0.523%5Ctimes5.9)
![Path\ length =3.09\ m](https://tex.z-dn.net/?f=Path%5C%20length%20%3D3.09%5C%20m)
(b). Angle = 30 rad
We need to calculate the path length
![Path\ length=30\times5.9](https://tex.z-dn.net/?f=Path%5C%20length%3D30%5Ctimes5.9)
![Path\ length=177\ m](https://tex.z-dn.net/?f=Path%5C%20length%3D177%5C%20m)
(c). Angle = 30 rev
We need to calculate the angle in rad
![\theta=30\times2\pi](https://tex.z-dn.net/?f=%5Ctheta%3D30%5Ctimes2%5Cpi)
![\theta=188.4\ rad](https://tex.z-dn.net/?f=%5Ctheta%3D188.4%5C%20rad)
We need to calculate the path length
![Path\ length=188.4\times5.9](https://tex.z-dn.net/?f=Path%5C%20length%3D188.4%5Ctimes5.9)
![Path\ length =1111.56\ m](https://tex.z-dn.net/?f=Path%5C%20length%20%3D1111.56%5C%20m)
Hence, (a). The path length is 3.09 m at 30°.
(b). The path length is 188.4 m at 30 rad.
(c). The path length is 1111.5 m at 30 rev.