Answer:
gravity pulled in clouds of dust and gas. which is sometimes referred to as a nebula.
Explanation:
<h2>Answer:</h2>
Acceleration= -1.11 m/sec²
<h2>Explanation:</h2>
Date Given to us is
Mass = 150 kg
Time = 1.5 minutes = 90 seconds
Distance = 2500 meters
Initial Velocity = 120 m/s
Final Velocity = 20 m/s
Acceleration = ?
<u>Solution:</u>
By using First Equation of motion
Vf = Vi + at
Putting the values
20 = 120 + a (90)
Subtracting 120 on both sides
20-120 = 120 + a(90) - 120
-100 = 90 a
Dividing both sides by 90
-100/90 = 90 a / 90
-1.11 = a
So the acceleration is -1.11 m/s²
So first Identify all the given Varibales so u can choose which Eqauton to use
D=200m
T=4s
Vi=10m/s
Vf=?
You should this equation
D= 0.50(Vf+Vi)T
Plug in the values
200= 0.50 (Vf+10) 4
Divide the 4 out of the right side and if you do sumthing to one side you gotta do it to the other
200 divided by 4= 0.50(Vf+10)
50= 0.50(Vf+10)
Now expand the 0.50
So 50= 0.5Vf + 5 (because 0.5 times 10 is 5)
Now get rid of the 5
50-5= 0.5Vf
45 =0.5Vf now Divide the 0.5 out
45 divided by 0.5 = Vf
And 45/0.5 is 90
So 90=Vf
Therefore the final Velocity is 90m/s
Answer:
The pencil is not pulled towards a person due to a very small magnitude of force between them, due to lighter masses.
Explanation:
Let us apply Newton's Law of Gravitation between a person and pencil.
Average Mass of a Normal Pencil = m₁ = 10 g = 0.01 kg
Average Mass of a Person = m₂ = 80 kg
Distance between both = r = 1 cm = 0.01 m (Taking minimal distance)
Gravitational Constant = G = 6.67 x 10⁻¹¹ N.m²/kg²
So,
F = Gm₁m₂/r²
F = (6.67 x 10⁻¹¹ N.m²/kg²)(0.01 kg)(80 kg)/(0.01 m)²
<u>F = 5.34 x 10⁻⁷ N</u>
This Force is very small in magnitude due to the light masses of both objects.
<u>Therefore, the pencil is not pulled towards a person due to a very small magnitude of force between them, due to lighter masses.</u>
Answer:
a) Δx ≈ 8.4 m
b) v ≈ 6.1 m/s
Explanation:
Given:
v₀ = 1.5 m/s
a = 2.1 m/s²
t = 2.2 s
a) Find: Δx
Δx = v₀ t + ½ at²
Δx = (1.5 m/s) (2.2 s) + ½ (2.1 m/s²) (2.2 s)²
Δx ≈ 8.4 m
b) Find: v
v = at + v₀
v = (2.1 m/s²) (2.2 s) + (1.5 m/s)
v ≈ 6.1 m/s
