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3 years ago

What mathematical formula is needed to determine the student's displacement from point A to C? (Hint: think

Physics

1 answer:

Anna35 [415]3 years ago

5 0

Answer:

The Pythagorean theorem

Explanation:

a^2+b^2=c^2

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Why do alpha particles and nuclei repel each other rather than attract eachother

Vesnalui [34]

Both have positive charge. In fact, an alpha particle IS a nucleus of a Helium atom.

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3 years ago

A car is traveling south at 70 miles per hour.

timama [110]

Answer:

velocity

Explanation:

velocity includes the direction taken by a person or object

4 0

3 years ago

Consider an electron near the Earth's equator. In which direction does it tend to deflect if its velocity is (a) directed downwa

Elenna [48]

The electron near the Earth's equator doesn't deflect if it's velocity is directed downwards.

Assume that north is directed along upwards, south is directed along downwards, east is directed along rightwards, and west is directed along leftwards.

The magnetic force on the charge q, moving with velocity v in the magnetic field B is given by

F=q(→v×→B)=qvBsinθ ..(1)

Here,

θ is the angle between the magnetic field and velocity.

Inside the Earth, the Earth's magnetic field is along northward (upwards), and the velocity is given to be along southwards (downwards) making an angle of 180°. In equation (1) sin180°=0. So, no magnetic force acts on the electron

Therefore,

The electron didn't deflect if it is directed downwards.

To know more about "Magnetic field"

Refer this link:

brainly.com/question/25573309

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2 years ago

Two subway stops are separated by 1210 m. If a subway train accelerates at 1.30 m/s2 from rest through the first half of the dis

solong [7]

Answer:

Part 1) Time of travel equals 61 seconds

Part 2) Maximum speed equals 39.66 m/s.

Explanation:

The final speed of the train when it completes half of it's journey is given by third equation of kinematics as

$v^{2}=u^2+2as$

where

'v' is the final speed

'u' is initial speed

'a' is acceleration of the body

's' is the distance covered

Applying the given values we get

$v^2=0+2\times 1.30\times \frac{1210}{2}\\\\v^{2}=1573\\\\\therefore v=39.66m/s$

Now the time taken to attain the above velocity can be calculated by the first equation of kinematics as

$v=u+at\\\\v=0+1.30\times t\\\\\therefore t=\frac{39.66}{1.30}=30.51seconds$

Since the deceleration is same as acceleration hence the time to stop in the same distance shall be equal to the time taken to accelerate the first half of distance

Thus total time of journey equals $T=2\times 30.51\approx61seconds$

Part b)

the maximum speed is reached at the point when the train ends it's acceleration thus the maximum speed reached by the train equals $39.66m/s$

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4 years ago

A 95-kilogram boy is running at a speed of 7 m/s. What is the boy’s kinetic energy?

Talja [164]

What is it anyone answer it now

6 0

3 years ago