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Natasha2012 [34]
3 years ago
10

Help fast please!

Chemistry
1 answer:
solong [7]3 years ago
6 0

NaOH + HBr=NaBr + H2O

sorry

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In one experiment 7.62 g of Fe are allowed to react with 8.67 g of S
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calculate moles of both reagents given and the moles of FeS that each of them would form if they were in excess  

moles = mass / molar mass  

moles Fe = 7.62 g / 55.85 g/mol  

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Therefore 7.62 g Fe can form 0.1364 moles FeS  

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The maximum amount of FeS possible is from complete reaction of all the limiting reagent.  

We have already determined that the Fe can form up to 0.1364 moles of FeS, so this is max amount of FeS you can get.  

Convert to mass

hope this helps :)

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