18m. It does not matter what direction the cat walked as long as it walked in a certain direction for said amount of distance
The model represents Photosynthesis. Light, carbon dioxide, and water are the reactants. The products will be Sugar and Oxygen. Photosynthesis releases oxygen and glucose. Which is the energy that living things need to survive.
860 mL.
<h3>Explanation</h3>
Separate this process into two steps:
- Cool the balloon from 305 K to 265 K.
- Reduce the pressure on the balloon from 0.45 atm to 0.25 atm.
What would be the volume of the balloon after each step?
After Cooling the balloon at constant pressure:
By Charles's Law, the volume of a gas is directly related to its temperature in degrees Kelvins.
In other words,
,
where
and
are volumes of the same gas.
and
are the temperatures (in degrees Kelvins) of that gas.
Rearranging,
.
The balloon ended up with a lower temperature. As a result, its volume drops:
.
After reducing the pressure on the balloon at constant temperature:
By Boyle's Law, the volume of a gas is inversely proportional to the pressure on this gas.
In other words,
,
where
and
are volumes of the same gas.
and
are the pressures on this gas.
Rearranging,
.
There's now less pressure on the balloon. As a result, the balloon will gain in volume:
.
The final volume of the balloon will be
.
Answer:
Here's what I get.
Explanation:
1. Brønsted-Lowry theory
An acid is a substance that can donate a proton to another substance.
A base is a substance that can accept a proton from another substance.
2. pH of ammonia
The chemical equation is

For simplicity, let's re-write this as

(a) Set up an ICE table.
B + H₂O ⇌ BH⁺ + OH⁻
I/mol·L⁻¹: 0.335 0 0
C/mol·L⁻¹: -x +x +x
E/mol·L⁻¹: 0.335 + x x x
![\rm K_{\text{b}} = \dfrac{\text{[BH}^{+}]\text{[OH}^{-}]}{\text{[B]}} = 1.8 \times 10^{-5}\\\\\dfrac{x^{2}}{0.335 - x} = 1.8 \times 10^{-5}](https://tex.z-dn.net/?f=%5Crm%20K_%7B%5Ctext%7Bb%7D%7D%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BBH%7D%5E%7B%2B%7D%5D%5Ctext%7B%5BOH%7D%5E%7B-%7D%5D%7D%7B%5Ctext%7B%5BB%5D%7D%7D%20%3D%201.8%20%5Ctimes%2010%5E%7B-5%7D%5C%5C%5C%5C%5Cdfrac%7Bx%5E%7B2%7D%7D%7B0.335%20-%20x%7D%20%3D%201.8%20%5Ctimes%2010%5E%7B-5%7D)
Check for negligibility:

(b) Solve for [OH⁻]
![\dfrac{x^{2}}{0.335} = 1.8 \times 10^{-5}\\\\x^{2} = 0.335 \times 1.8 \times 10^{-5}\\x^{2} = 6.03 \times 10^{-6}\\x = \sqrt{6.03 \times 10^{-6}}\\x = \text{[OH]}^{-} = \mathbf{2.46 \times 10^{-3}} \textbf{ mol/L}](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%5E%7B2%7D%7D%7B0.335%7D%20%3D%201.8%20%5Ctimes%2010%5E%7B-5%7D%5C%5C%5C%5Cx%5E%7B2%7D%20%3D%200.335%20%5Ctimes%201.8%20%5Ctimes%2010%5E%7B-5%7D%5C%5Cx%5E%7B2%7D%20%3D%206.03%20%5Ctimes%2010%5E%7B-6%7D%5C%5Cx%20%3D%20%5Csqrt%7B6.03%20%5Ctimes%2010%5E%7B-6%7D%7D%5C%5Cx%20%3D%20%5Ctext%7B%5BOH%5D%7D%5E%7B-%7D%20%3D%20%5Cmathbf%7B2.46%20%5Ctimes%2010%5E%7B-3%7D%7D%20%5Ctextbf%7B%20mol%2FL%7D)
(c) Calculate the pOH
![\text{pOH} = -\log \text{[OH}^{-}] = -\log(2.46 \times 10^{-3}) = 2.61](https://tex.z-dn.net/?f=%5Ctext%7BpOH%7D%20%3D%20-%5Clog%20%5Ctext%7B%5BOH%7D%5E%7B-%7D%5D%20%3D%20-%5Clog%282.46%20%5Ctimes%2010%5E%7B-3%7D%29%20%3D%202.61)
(d) Calculate the pH
pH = 14.00 - pOH = 14.00 - 2.61 = 11.39
Gravitational potential energy, mechanical energy, and kinetic energy.