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Jobisdone [24]
3 years ago
11

Find the value of x if A,B,and C are collinear points and B is between A and C. AB=3x, BC=2x-7, AC=2x+35

Mathematics
2 answers:
Mariana [72]3 years ago
6 0

Answer:

x = 14

Step-by-step explanation:

3x+2x-7=2x+35

then solve for x

bekas [8.4K]3 years ago
3 0

<u>Answer:</u>

x = 14

<u>Step-by-step explanation:</u>

We are given that A, B and C are collinear points and B is in between A and C.

The length from A to B is 3 x, length from B to C is 2x - 7 and AC is 2 x + 35.

We are to find the value of x.

A B + B C = A C

3 x + 2 x - 7 = 2 x + 3 5

3 x + 2 x - 2 x = 3 5 + 7

3 x = 4 2

x = \frac { 4 2 } { 3 }

x = 14

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For each carbon-14 atom, there are approximately 10^12 carbon-12 atoms. This ratio is constant in each organism. The carbon-12 r
Bond [772]

Answer:

1) There are 100 carbon-14 atoms in the wood when it died

2) A function that models the number 'N' of carbon-14 atoms present in the wood (t) years after it died is  presented as follows;

N = 100 \times \left (\dfrac{1}{2} \right )^{\dfrac{t}{5,730} }

Step-by-step explanation:

The given parameters are;

The number of carbon-12 for each carbon-14 atom ≈ 10¹² carbon-12 atoms

The number of carbon-12 in the piece of wood = 10¹⁴ carbon-12 atoms

The number of carbon-14 in the piece of wood = 40 carbon-14 atoms

The number of carbon-12 in an organism = Constant

The number of carbon-14 in an organism = Decays

1) Given that the number of carbon-12 in an organism is constant, and there are 10¹² carbon-12 atoms per each carbon-14 atom, therefore, we have;

The number of carbon-12 atoms in the wood when it died = 10¹⁴ carbon-12 atoms

The number of carbon-14 atoms in the wood when it died = (10¹⁴ carbon-12 atoms)/(10¹² carbon-12 atoms/(carbon-14 atom)) = 100 carbon-14 atoms

The number of carbon-14 atoms in the wood when it died = 100 carbon-14 atoms

2) The half life of a radioactive isotope is given by the following formula;

N(t) = N_0 \cdot \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{\frac{1}{2} }} }

The half life of carbon-14 atoms, t_{\frac{1}{2} } ≈ 5,730 years

N₀ = The amount of carbon-14 present in the wood when it died = 100 carbon-14 atoms

Therefore, we have;

The number, N, of carbon-14 atoms present in the wood (t) years after it died is given as follows;

N = 100 \times \left (\dfrac{1}{2} \right )^{\dfrac{t}{5,730} }

3 0
3 years ago
Use the interactive ruler to determine the lengths of the line segments
Liono4ka [1.6K]

Answer:

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8 0
3 years ago
What is the y-value of the solution to the system of equations?
alukav5142 [94]

Let's solve for x first,


3x + 5y - 5y = 1 - 5y

3x/3 = 1/3 - 5y/3

x = 1/3 - 5/3y


Let's now plug that into the other equation,


7(1/3 - 5/3y) + 4y = -13

7/3 - 35/3y + 4y = -13

7/3 - 7 2/3y - 7/3 = -13 - 7/3

- 7 2/3y (-3/23) = -15 1/3 (-3/23)

y = 2



The answer is 2

4 0
4 years ago
Evaluate. 43⋅(10025)−50
inna [77]
The dot means to mutiply
so 43 x 10025 -50
since BEDMAS is applied,
we would do the multiplication first
43 x 10025 = 431075 
and <span>431075 - 50 is 431025
FINAL ANSWER: 431025</span>
7 0
3 years ago
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The drain in your 45-gallon bathtub is partially clogged, but you need to take a shower. The shower head had a flow rate of 2.25
Helen [10]

Answer:

Time = 1.978\ min

Step-by-step explanation:

Given

R_1 = 2.25\ gal/min --- Flow rate of the shower

R_2 = 20.5\ gal/min --- Drain rate of the bathtub

Size = 45gal -- Bathtub size

Required

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R_3 = R_1 + R_2

R_3 = 2.25 + 20.5

R_3 = 22.75gal/min

The maximum time of shower is:

Time = \frac{Size}{R_3}

Time = \frac{45gal}{22.75gal/min}

Time = 1.978\ min  

6 0
3 years ago
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