We have trapezoid with congruent legs.
30x + 11y = 2x + 3
28x +11y = 3
Also we have
30x + 11y = 12
We got 2 equations:
30x + 11y = 12
28x +11y = 3 (*-1) -----> -28x -11y = -3
30x + 11y = 12
<u> -28x -11y = -3</u>
2x = 9
x=9/2
30x + 11y = 12 ------> 30*9/2 +11y =12 ------> 135+11y =12, ---> 11y = - 123,
y= - 123/11
Answer:
y = |x| + 3.
Step-by-step explanation:
The movement of the y value from 1 to 4 is a translation of 3 units upwards.
The graph is y = |x| + 3.
Sarah got £48, Liam got £32, and Emily got £112
Hi!
We can use <u>point-slope form </u>to solve this.

<em> and </em>
<em> will be from one of the points.</em>
<u>First, we have to find </u>
<u>, the slope. We can use the slope equation to get this.</u>

<em>Plug in your points:</em>

Your slope is 
<u><em>Now plug points and slope into point-slope equation. We will use (8, 4).</em></u>

Now, if you want to get it into y = mx + b form, you have to solve for y:



Your equation is 
<u><em>For more information on how to get the equation of a line when given two points, see here:</em></u>
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