Answer:
Thermal Energy
Explanation:
I'll give you an example, Rub your hands together. Then touch your face or leg to feel any temperature change. Most likely your hands are warmer.
Answer:
a) ammonium ion
b) amide ion
Explanation:
The order of decreasing bond angles of the three nitrogen species; ammonium ion, ammonia and amide ion is NH4+ >NH3> NH2-. Next we need to rationalize this order of decreasing bond angles from the valence shell electron pair repulsion (VSEPR) theory perspective.
First we must realize that all three nitrogen species contain a central sp3 hybridized carbon atom. This means that a tetrahedral geometry is ideally expected. Recall that the presence of lone pairs distorts molecular structures from the expected geometry based on VSEPR theory.
The amide ion contains two lone pairs of electrons. Remember that the presence of lone pairs causes greater repulsion than bond pairs on the outermost shell of the central atom. Hence, the amide ion has the least H-N-H bond angle of about 105°.
The ammonia molecule contains one lone pair, the repulsion caused by one lone pair is definitely bless than that caused by two lone pairs of electrons hence the bond angle of the H-N-H bond in ammonia is 107°.
The ammonium ion contains four bond pairs and no lone pair of electrons on the outermost nitrogen atom. Hence we expect a perfect tetrahedron with bond angle of 109°.
Answer : The compound that would be most soluble in water is CH3CH2CH2OH
Explanation :
Water is a polar solvent and can dissolve polar molecules. This is based on the principle "Like dissolves like".
Among the given molecules, CH3CH2CH2CH3 is a hydrocarbon known as butane. All hydrocarbons are non polar. Therefore this compound will not be soluble in water.
The remaining compounds are polar, but Ch3CH2CH2OH shows greater solubility in water owing to presence of hydrogen bonding.
Hydrogen bonding is a type of intermolecular force that gets formed when a compound has hydrogen atom directly attached to highly electro-negative N, F or O atom.
When CH3CH2CH2OH is dissolved in water, it forms hydrogen bonds with water molecules. Due to this hydrogen bonding, the molecule shows greater solubility.
Therefore CH3CH2CH2OH is the most soluble compound in water
An electric current can be carried through a metal by the free flow of the shared electrons.
The balance chemical equation is :
2HCL + Na2CO3 -----> 2NaCl + H2O + CO2
According to Question,
Given,
Molarity of HCL = 1.75 m
Sodium Carbonate (Na2CO3) = 0.100 m
For finding out the molarity,
c = n solute / Vsolution => n = c.Vsolution
nCO^2-3 = 0.100 mol L^-1 . 0.750 L = 0.0750 moles of CO^2-3
0.0750 moles of CO^2-3 . 2 moles H3O^+ / 1 mole CO^2-3
= 0.150 moles of H3O^+
As we have already know the molarity of HCL , we easily calculate what volumes by many moles.
c = nsolute / Vsolution => Vsolution = nsolute / c
VH3O^+ = 0.150 moles / 1.75 mol L^-1 = 0.0857 L
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