Part G
1 answer:
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Explanation:
Molarity of copper sulfate solution = 1.00 M
Volume of the copper sulfate solution = 50.0 mL = 0.050 L
Moles of copper sulfate = n
n = 0.050 L × 1.00 M= 0.050 mol
1 mol of copper sulfate has 1 mol of copper . Then 0.050 mol of copper sulfate has :
of copper
a) Mass of 0.050 moles of copper = 0.050 mol × 63.5 g/mol =3.175 g
b) The identity of the compound which formed after the reaction is copper hydroxide.
c) The complete equation for the reaction that occurs when copper sulfate and potassium hydroxide are mixed:
d) ..[1]
..[2]
Common ion both sides are removed. The net ionic equation is given as:
e) Volume of solution after mixing of both solution,V= 50 mL + 50ml = 100 mL
Mass of final solution ,m= 1 mL
Density of solution ,d= 1 g/mL (same as pure water)
Heat capacity of the solution = c = 4.186 J/g°C (same as pure water)
Change in temperature of the solution,ΔT = 27.7 °C- 21.5 °C=6.2°C
Enthalpy of the reaction = ΔH =
ΔH =
The ΔH for the reaction that occurs on mixing is 51.90 kJ/mol.