Answer:
259 mg is the mass of silver chloride required to plate 195 mg of pure silver.
Explanation:
Silver chloride contains 75.27 percent silver. It can be concluded that:-
For every 100 mg of silver chloride, 75.27 mg of silver we can get.
So, to produce 195 mg of silver, the amount of silver chloride required can be calculated as:-
<u>259 mg is the mass of silver chloride required to plate 195 mg of pure silver.</u>
Answer: 
molecules of 
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 
of particles.
To calculate the moles, we use the equation:
1 mole of contains = molecules
0.128 mole of contains = 
molecules
Thus there are molecules of
the Empirical formula of the compound is calculated as follows
find the moles of each element
moles = mass/molar mass
that is Magnesium= 0.564 g /24 g/mol = 0.0235 moles
For oxygen = 0.376 g /16 g/mol= 0.0235 moles
find the mole ratio by dividing both moles of by 0.0235 moles
magnesium = 0.0235/0.0235= 1mole
oxygen= 0.0235 /0.0235= 1mole
therefore the empirical formula = MgO
C, they could work together to make things from the top down.
