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3 years ago

Why are metals good conductors of electric current

Chemistry

2 answers:

castortr0y [4]3 years ago

6 0

An electric current can be carried through a metal by the free flow of the shared electrons.

Tomtit [17]3 years ago

6 0

they have freely-moving electrons.

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What is a device that changes electrical energy into mechanical energy?

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<span>A generator converts mechanical energy into electrical energy, while a motor does the opposite - it converts electrical energy into mechanical energy.</span>

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3 years ago

I am the life cycle that contains tiny undeveloped plants,

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The water cycle regardless if it is in a lake, our bodies, food, or underground.

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2 years ago

Solid NaI is slowly added to a solution that is 0.0079 M Cu+ and 0.0087 M Ag+.Which compound will begin to precipitate first?NaI

NeTakaya

Answer :

AgI should precipitate first.

The concentration of $Ag^+$ when CuI just begins to precipitate is, $6.64\times 10^{-7}M$

Percent of $Ag^+$ remains is, 0.0076 %

Explanation :

$K_{sp}$ for CuI is $1\times 10^{-12}$

$K_{sp}$ for AgI is $8.3\times 10^{-17}$

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgI has a smaller than CuI then AgI should precipitate first.

Now we have to calculate the concentration of iodide ion.

The solubility equilibrium reaction will be:

$CuI\rightleftharpoons Cu^++I^-$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Cu^+][I^-]$

$1\times 10^{-12}=0.0079\times [I^-]$

$[I^-]=1.25\times 10^{-10}M$

Now we have to calculate the concentration of silver ion.

The solubility equilibrium reaction will be:

$AgI\rightleftharpoons Ag^++I^-$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ag^+][I^-]$

$8.3\times 10^{-17}=[Ag^+]\times 1.25\times 10^{-10}M$

$[Ag^+]=6.64\times 10^{-7}M$

Now we have to calculate the percent of $Ag^+$ remains in solution at this point.

Percent of $Ag^+$ remains = $\frac{6.64\times 10^{-7}}{0.0087}\times 100$

Percent of $Ag^+$ remains = 0.0076 %

8 0

3 years ago

When a piece of metal is irradiated with UV radiation (λ = 162 nm), electrons are ejected with a kinetic energy of 3.54×10-19 J.

dsp73

We have that the work function of the metal

$\phi=1.227*10^{-18}J$

From the Question we are told that

UV radiation (λ = 162 nm)

Kinetic energy $K.E =3.54*10-19 J.$

Generally the equation for Kinetic energy is mathematically given as

$KE =\frac{hc}{\pi-\phi} \\\\\phi =\frac{ 6.626*10^{-34} * 3*10^8}{162*10^{-9} -3.54*10^{-19}}$

$\phi=1.227*10^{-18}J$

For more information on this visit

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3 years ago

If 5.0 moles of C3H8 react, how many molecules of water are formed?

artcher [175]

Balance Chemical Equation for combustion of Propane is as follow,

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

According to equation,

1 mole of C₃H₈ on combustion gives = 4 moles of H₂O
So,
5 moles of C₃H₈ on combustion will give = X moles of H₂O

Solving for X,
X = (5 mol × 4 mol) ÷ 1 mole

X = 20 moles of H₂O

Calculating number of molecules for 20 moles of H₂O,
As,
1 mole of H₂O contains = 6.022 × 10²³ molecules
So,
20 moles of H₂O will contain = X molecules

Solving for X,
X = (20 mole × 6.022 × 10²³ molecules) ÷ 1 mol

X = 1.20 ×10²⁵ Molecules of H₂O

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3 years ago