Answer:
1.74 m/s
Explanation:
From the question, we are given that the mass of the an object, m1= 2.7 kilogram(kg) and the mass of the can,m(can) is 0.72 Kilogram (kg). The velocity of the mass of an object(m1) , V1 is 1.1 metre per seconds(m/s) and the velocity of the mass of can[m(can)], V(can) is unknown- this is what we are to find.
Therefore, using the formula below, we can calculate the speed of the can, V(can);
===> Mass of object,m1 × velocity of object, V1 = mass of the can[m(can)] × velocity is of the can[V(can)].----------------------------------------------------(1).
Since the question says the collision was elastic, we use the formula below
Slotting in the given values into the equation (1) above, we have;
1/2×M1×V^2(initial velocity of the first object) + 1/2 ×M(can)×V^2(final velocy of the first object)= 1/2 × M1 × V^2 m( initial velocity of the first object).
Therefore, final velocity of the can= 2M1V1/M1+M2.
==> 2×2.7×1.1/ 2.7 + 0.72.
The velocity of the can after collision = 1.74 m/s
Parallax angles of less than 0.01 arcsec are very difficult to measure from Earth because of the effects of the Earth's atmosphere. This limits Earth based telescopes to measuring the distances to stars about 1/0.01 or 100 parsecs away.
Answer:2500kg
Explanation:
Weight of car(w)=25000N
Acceleration due to gravity approximately(g) 10m/s^2
Mass=w/g
Mass=25000/10
Mass=2500kg
<span>It gains an electron.</span>
Answer:
6
Explanation:
Following are the possible transition
1 ) 4 to 3
2) 4 to 2
3) 4 to 1
4 ) 3 to 2
5 ) 3 to 1
6 ) 2 to 1 .
There are altogether 6 wavelengths of photons possible .
This result can be achieved with the help of permutation and combination.
No of ways in which 2 things can be selected out of 4 things , combination being all different.
₂C⁴ = (4 X 3) / 2 = 6.
