The magnet (south pole of the magnet) has magnetized the right side of the block.
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Direction of electric field in the magnetic material</h3>
The direction of electric field of the atom of the magnetic material is unpolarized.
From the diagram in the image, the right hand side of the magnetic material is being attracted to south pole of the magnet.
Thus, we can conclude that, the magnet has magnetized the right side of the block.
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Answer: The rate at which water moves through the plants due to transpiration plays an important role in maintaining plant water balance. ... This moves water and other nutrients absorbed by roots to the shoots and other parts of the plant. Hence, transpiration is very important for the survival and productivity of plants.
Explanation: the explanation of the answers is that Advantages of a dry cell are:
The compact size of a dry cell makes it suitable for powering small electronic devices.(toys, flashlights, portable radios, cameras, hearing aids). The electrolyte used in dry cell is relatively not so harmful to the environment. Dry cells are inexpensive. The main disadvantage of a dry cell is that it cannot be recharged once it loses its electrical power, Because when the cells turn any color then you are died.
Answer:
All adjustments in issue include changes in energy. Energy is either delivered or consumed. The energy is often in the form of heat, however it might be in the form of sound or light.
Explanation:
this is in my own words btw:)
Answer:
At 3.86K
Explanation:
The following data are obtained from a straight line graph of C/T plotted against T2, where C is the measured heat capacity and T is the temperature:
gradient = 0.0469 mJ mol−1 K−4 vertical intercept = 0.7 mJ mol−1 K−2
Since the graph of C/T against T2 is a straight line, the are related by the straight line equation: C /T =γ+AT². Multiplying by T, we get C =γT +AT³ The electronic contribution is linear in T, so it would be given by the first term: Ce =γT. The lattice (phonon) contribution is proportional to T³, so it would be the second term: Cph =AT³. When they become equal, we can solve these 2 equations for T. This gives: T = √γ A .
We can find γ and A from the graph. Returning to the straight line equation C /T =γ+AT². we can see that γ would be the vertical intercept, and A would be the gradient. These 2 values are given. Substituting, we f ind: T =
√0.7/ 0.0469 = 3.86K.
Using sound waves, sonar signals allow oceanographers to determine ocean depth.
