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pshichka [43]
3 years ago
11

Provides some background for this problem. a ball is thrown vertically upward, which is the positive direction. a little later i

t returns to its point of release. the ball is in the air for a total time of 7.70 s. what is its initial velocity? neglect air resistance.
Physics
1 answer:
julsineya [31]3 years ago
6 0
For an object thrown vertically upward, its time of flight is equal to the equation below:

t = 2v/g
where
t is the time of flight
v is the initial velocity
g is the acceleration due to gravity equal to 9.81 m/s²

Substituting the values,

7.07 = 2v/9.81
v = 34.68 m/s
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A ball with 100 J of PE is released from a height of 10 m. What will be the KE of the ball at 5
harkovskaia [24]

Answer:

The kinetic energy is: 50[J]

Explanation:

The ball is having a potential energy of 100 [J], therefore

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E_{p} =m*g*h\\where:\\g= gravity[m/s^{2} ]\\m = mass [kg]\\m= \frac{E_{p} }{g*h}\\ m= \frac{100}{9.81*10}\\\\m= 1.01[kg]\\\\

In the moment when the ball starts to fall, it will lose potential energy and the potential energy will be transforme in kinetic energy.

When the elevation is 5 [m], we have a potential energy of

P_{e} =m*g*h\\P_{e} =1.01*9.81*5\\\\P_{e} = 50 [J]\\

This energy is equal to the kinetic energy, therefore

Ke= 50 [J]

8 0
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Which of the following is true when an object of mass m moving on a horizontal frictionless surface hits and sticks to an object
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Answer:

c)

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2 years ago
Ice floats on water.​
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Answer:

Yeah ice floats on water.

Observation

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