Answer:
C. Marie should make sure she surveys both the fathers and mothers.
Answer:
Step-by-step explanation:
Time taken in each lap = 4 min
Total laps = 11
Total time = 11 x 4 = 44min
These are just a few of the things you will learn in 6th grade. You will learn how to write a two- variable equation, how to identify the graph of an equation, graphing two-variable equations. how to interpret a graph and a word problem, and how to write an equation from a graph using a table, two-dimensional figures,Identify and classify polygons, Measure and classify angles,Estimate angle measurements, Classify triangles, Identify trapezoids, Classify quadrilaterals, Graph triangles and quadrilaterals, Find missing angles in triangles, and a lot more subjects. <span><span><span>Find missing angles in quadrilaterals
</span><span>Sums of angles in polygons
</span><span>Lines, line segments, and rays
</span><span>Name angles
</span><span>Complementary and supplementary angles
</span><span>Transversal of parallel lines
</span><span>Find lengths and measures of bisected line segments and angles
</span><span>Parts of a circle
</span><span>Central angles of circles</span></span>Symmetry and transformations
<span><span>Symmetry
</span><span>Reflection, rotation, and translation
</span><span>Translations: graph the image
</span><span>Reflections: graph the image
</span><span>Rotations: graph the image
</span><span>Similar and congruent figures
</span><span>Find side lengths of similar figures</span></span>Three-dimensional figures
<span><span>Identify polyhedra
</span><span>Which figure is being described
</span><span>Nets of three-dimensional figures
</span><span>Front, side, and top view</span></span>Geometric measurement
<span><span>Perimeter
</span><span>Area of rectangles and squares
</span><span>Area of triangles
</span><span>Area of parallelograms and trapezoids
</span><span>Area of quadrilaterals
</span><span>Area of compound figures
</span><span>Area between two rectangles
</span><span>Area between two triangles
</span><span>Rectangles: relationship between perimeter and area
</span><span>compare area and perimeter of two figures
</span><span>Circles: calculate area, circumference, radius, and diameter
</span><span>Circles: word problems
</span><span>Area between two circles
</span><span>Volume of cubes and rectangular prisms
</span><span>Surface area of cubes and rectangular prisms
</span><span>Volume and surface area of triangular prisms
</span><span>Volume and surface area of cylinders
</span><span>Relate volume and surface area
</span><span>Semicircles: calculate area, perimeter, radius, and diameter
</span><span>Quarter circles: calculate area, perimeter, and radius
</span><span>Area of compound figures with triangles, semicircles, and quarter circles</span></span>Data and graphs
<span><span>Interpret pictographs
</span><span>Create pictographs
</span><span>Interpret line plots
</span><span>Create line plots
</span><span>Create and interpret line plots with fractions
</span><span>Create frequency tables
</span><span>Interpret bar graphs
</span><span>Create bar graphs
</span><span>Interpret double bar graphs</span><span>
</span></span><span>
</span></span>
<u>x = 9</u>
Step-by-step explanation:
mean = 5+7+7+x /4 = 7
19+x / 4 = 7
19+x = 28
x = 9
Given:
Either has a school certificate or diploma or even both = 20 people
Having school certificates = 14
Having diplomas = 11
To find:
The number of people who have a school certificate only.
Solution:
Let A be the set of people who have school certificates and B be the set of people who have diplomas.
According to the given information, we have
We know that,
Subtract both sides by 25.
We need to find the number of people who have a school certificate only, i.e. 
.
Therefore, 9 people have a school certificate only.
