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alexira [117]
2 years ago
10

Find x. I had been stuck on this one for awhile

Mathematics
1 answer:
Arlecino [84]2 years ago
4 0

Answer:

34 degrees

Step-by-step explanation:

ok so 180-111=69

then the opposite angle from 37 is also 37

the the missing angle from the left triangle has to be 103

so then the angle below x is 77

and so we know x = 34 degrees

I hope that made sense.

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The line $y = 3$ intersects the graph of $y = 4x^2 + x - 1$ at the points $A$ and $B$. The distance between $A$ and $B$ can be w
raketka [301]

Answer:

61

Step-by-step explanation:

Let's find the points A and B.

We know that the y-coordinates of both are 3.

So let's first solve:

3=4x^2+x-1

Subtract 3 on both sides:

0=4x^2+x-1-3

Simplify:

0=4x^2+x-4

I'm going to use the quadratic formula, x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}, to solve.

We must first compare to the quadratic equation, ax^2+bx+c=0.

a=4

b=1

c=-4

\frac{-1 \pm \sqrt{1^2-4(4)(-4)}}{2(4)}

\frac{-1 \pm \sqrt{1+64}}{8}

\frac{-1 \pm \sqrt{65}}{8}

Since the distance between the points A and B is horizontal. We know this because they share the same y-coordinate.This means we just need to find the positive difference between the x-values we found for the points of A and B.

So that is, the distance between A and B is:

\frac{-1+\sqrt{65}}{8}-\frac{-1-\sqrt{65}}{8}

\frac{-1+\sqrt{65}+1+\sqrt{65}}{8}

\frac{2\sqrt{65}}{8}

\frac{\sqrt{65}}{4}

If we compare this to \frac{\sqrt{m}}{n}, we should see that:

m=65 \text{ and } n=4.

So m-n=65-4=61.

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3 years ago
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Answer: A


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(x, y)

So if we take all the numbers on the left, we get 1, 2, 3, and 6. Thus, our domain is {1,2,3,6}


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27−9x−9(x+4)=

27−9x−(9x+36)=


27−9x−9x−36=


Collect like terms.

(27−36)+(−9x−9x)= −9−18x
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