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Anika [276]
3 years ago
6

Calculate the impulse imparted when a 3,000-kg car hits a wall at 60 . m/s and comes to a stop.

Physics
1 answer:
Pani-rosa [81]3 years ago
7 0

Impulse = change in momentum


The answer is 0.

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Identify the three types of isometric transformations. A. reflection, rotation, translation B. reflection, rotation, dilation C.
inessss [21]
<span>reflection, rotation, translation</span>
4 0
3 years ago
How do atoms become more chemically stable?
Marat540 [252]

Answer:

For an atom to become totally stable, it needs to have a full outer shell. To do this, two or more atoms will share or give away electrons to each other in a process called bonding.

Explanation:

When an atom loses or gains an electron, it becomes an ion. If it gains an electron, it's a cation, and if it loses one, it's an anion. This happens most commonly in chemical reactions, in which atoms share electrons to form a stable outer shell of 8. For example, the water molecule consists of two hydrogen atoms and an oxygen atom.

3 0
3 years ago
What is the kinetic energy of a bike with a mass of 24 kg traveling at 3 m/s?
erastovalidia [21]

Answer:

KE = 1/2mv^2

KE = 1/2(24)(3^2)

KE = 12(9)

KE = 108 J

Let me know if this helps!

5 0
3 years ago
A train at rest emits a sound at a frequency of 1057 Hz. An observer in a car travels away from the sound source at a speed of 2
il63 [147K]

Answer:

993.52 Hz

Explanation:

The frequency of sound emitted by the stationery train is 1057 Hz.

The car travels away from the train at 20.6 m/s.

The frequency the observer hears is given by the formula:

f_o = \frac{v - v_o}{v}f

where v = velocity of sound = 343 m/s

vo = velocity of observer

f = frequency from source

This phenomenon is known as Doppler's effect.

Therefore:

f_o = \frac{343 - 20.6}{343} * 1057\\ \\f_o = 322.4 / 343 * 1057\\\\f_o = 993.52 Hz

The frequency heard by the observer is 993.52 Hz.

4 0
3 years ago
Consider four atoms from the second period: lithium, beryllium, boron, carbon, and nitrogen. Which of these emblems has the lowe
xz_007 [3.2K]
If you go to the right along the periodic table, electronegativity increases.
So the larger the column number, the greater the electronegativity.

-Lithium has lowest as it is in the 1st column



-Beryllium (2nd column)
-Boron s (13th column)
-Nitrogen (15th column)


6 0
3 years ago
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