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Zina [86]
2 years ago
5

How many days are in 345000 minutes? (Set up by dimensional analysis)​

Physics
1 answer:
Komok [63]2 years ago
3 0
239.583 days is the answer
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An elevator accelerates upward at 2.0 m/s?,
amm1812

Answer:

Force the floor exerts on the  passenger is 833 N.

Explanation:

  • Weight of passenger (F_{g}) = mg = 85 × 9.8 N = 833 N
  • Force the floor exerts on the  passenger (F_{N}) = ?
  • For the elevator with the speed as 2.0 m/s the net force is zero, it means that the force is balanced.

                                       i.e. F_{N} = - F_{g} = -mg = 833 N

                                       hence  F_{N} is 833 N

  • If the lift was not at a constant speed i.e. if it had acceleration (m/s^{2})  then the case would be different.

4 0
3 years ago
Please help for 21! will mark brainliest
Katyanochek1 [597]

The answer for this question is D

5 0
2 years ago
Which statement is true of the electric field at a distant from the source of charge?
iVinArrow [24]

Answer:

A negative charge, if free to move in an electric field, will move from a low potential point to a high potential point. To move a positive charge against the electric field, work has to be done by you or a force external to the field.

Explanation:

Mark as Brainliest plz!!!

8 0
3 years ago
A cyclist rides at 6.20 m/s through a intersection. A stationary car begins to
Xelga [282]

Answer:

The width of the intersection is 20 meters

Explanation:

The speed with which the cyclist is riding, v₁ = 6.20 m/s

The rate at which the car starts to accelerate, a = 3.844 m/s²

The initial velocity of the car = The car is stationary at the start = 0 m/s

The time at which the cyclist and the car reach the other side of the intersection = The same time;

Let 't' represent the time at which the cyclist and the car both reach the other side of the intersection, we have;

The distance travelled by the cyclist = The distance traveled by the car

∴ v₁ × t = 1/2 × a × t²

Plugging in the values for 'v₁', and 'a' in the above equation, we get;

6.20 × t = 1/2 × 3.844 × t²

∴ 1.922·t² - 6.20·t = 0

∴ t·(1.922·t - 6.20) = 0

t = 0, or t = 6.20/1.922 = 100/31

The time at which the cyclist and the car both reach the other side of the intersection, t = 100/31 seconds

The with of the intersection, w = v₁ × t

∴ w = 6.20 × 100/31 = 100/5 = 20

The width of the intersection, w = 20 meters.

8 0
3 years ago
Find the mass of a body if the acceleration the body used to move is given as 5 m/s-2 and the force of the body is 30N take g=10
Aleonysh [2.5K]

The mass of a body if the acceleration the body used to move is given as 5 m/s-2 will be 3 kg.

<h3>What is force?</h3>

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

Given data;

Force,F = 30 N

Mass,m =  kg

Acceleration,a = 5 m/s²

The force is found as;

F=ma

30 N =m kg × 5 m/s²

m=3 kg

Hence the mass of a body will be 3 kg.

To learn more about the force refer to the link;

brainly.com/question/26115859#SPJ1

#SPJ1

7 0
2 years ago
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