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3 years ago

Which has more gravitational potential energy: a 300 N cat at a height of 6 meters or a 50 N bird at a height of 50 meters

Physics

1 answer:

Zolol [24]3 years ago

7 0

Gravitational Potential energy is given by the formula

$U = mgH$

so it is product of weight of object and its height

for PE of cat weight is given as 300 N at height 6 m

$U_1 = 300 \times 6 = 1800 J$

on other side we will have a bird of 50 N weight with height 50 m

$U_2 = 50 \times 50 = 2500 J$

now here we can see that it depends on the product of weight and height both

so here PE of bird will be more than the PE of Cat

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A machine exerts a 100 N force to the right over a 5.00 meter length in 4.00 seconds. Calculate the power output of this machine

bixtya [17]

125 W is the power output of this machine.

Answer:

Explanation:

Power is defined as the amount of work done on the system to move that system from its original state within the given time interval. So it can be determined by the ratio of work done with time interval. As work done is the measure of force required to move a system to a certain distance. Work done is calculated as product of force with displacement.

So in the present case, the force is given as 100 N, the displacement is given as 5 m and the time is given as 4 s, then power is

$Power = \frac{Work done}{Time}$

As Work done = Force acting on the machine × Displacement

So $Power = \frac{(Force * Displacement)}{Time}$

Power = $\frac{(100*5)}{4}$ =125 W

So, 125 W is the power output of this machine.

6 0

3 years ago

A car is driven 13 mi east and then certain distance due north, ending up at the position 25 degrees north of east of its initia

Kobotan [32]

Answer: Hello mate!

lets define the north as the y-axis and east as the x-axis.

Using the notation (x,y) we can define the initial position of the car as (0,0)

then the car travells 13 mi east, so now the position is (13,0)

then the car travels Y miles to the north, so the position now is (13, Y)

and we know that the final position is 25° degrees north of east of the initial position. This angle says that the distance traveled to the north is less than 13 mi because this angle is closer to the x-axis (or east in this case).

This angle is measured from east to north, then the adjacent cathetus is on the x-axis, in this case, 13mi

And we want to find the distance Y, so we can use the tangent:

Tan(25°) = Y/13

tan(25°)*13 mi = Y = 6.06 mi.

3 0

3 years ago

Astronomers observe the motion of four planets that orbit a star similar to the Sun. Each planet follows an elliptical orbit aro

Sergeu [11.5K]

Answer:

planet that is farthest away is planet X

kepler's third law

Explanation: