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strojnjashka [21]
4 years ago
11

Which has more gravitational potential energy: a 300 N cat at a height of 6 meters or a 50 N bird at a height of 50 meters

Physics
1 answer:
Zolol [24]4 years ago
7 0

Gravitational Potential energy is given by the formula

U = mgH

so it is product of weight of object and its height

for PE of cat weight is given as 300 N at height 6 m

U_1 = 300 \times 6 = 1800 J

on other side we will have a bird of 50 N weight with height 50 m

U_2 = 50 \times 50 = 2500 J

now here we can see that it depends on the product of weight and height both

so here PE of bird will be more than the PE of Cat

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What minimum heat is needed to bring 150 g of water at 20 ∘c to the boiling point and completely boil it away? the specific heat
AnnZ [28]

Try this solution:

if given m=0.15 kg; t₁=20 °C; t₂=100 °C; c=4190 J/(kg*C); q=226*10⁴ J/kg., then


Q=Q₁+Q₂,

where Q₁=cm(t₂-t₁) and Q₂=q*m.

Finally,

Q=cm(t₂-t₁)+qm;

Q=4190*0.15*80+2240000*0.15=386280 J=<u>386.28 kJ</u>.

4 0
3 years ago
a car having an initial velocity of 6 m/s east slows uniformly to 2 m/s east in 2.0 s what is the acceleration of the car during
melomori [17]

Answer:

-1 m/s/s West

Explanation:

Vf = Vi + at

2 = 6 + 4a

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a = -1

7 0
3 years ago
How much force can a 2.5 kg sledge hammer excerpt on a nail if you can swing the hammer at 20 m/s and the hammer contacts the na
AleksAgata [21]

Answer:

625 N

Explanation:

The impulse given to the nail is equal to the change in momentum of the hammer:

I=F \Delta t=m \Delta v

where

F is the force exerted by the hammer

\Delta t=0.08 s is the time of contact

m=2.5 kg is the mass

\Delta v=20 m/s is the change in velocity of the hammer

Substituting the data and re-arranging the equation, we can find the force:

F=\frac{m \Delta v}{\Delta t}=\frac{(2.5 kg)(20 m/s)}{0.08 s}=625 N

4 0
4 years ago
The speed of propagation of electrical signals in a nerve cell depends on the diameter of the axon (nerve fiber). If the nerve c
gayaneshka [121]

Answer:

61 ms

Explanation:

Given that

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In solving this, we'd apply the very most basic formula in physics. Formula of speed, with respect to time and distance.

Speed, v = distance, s / time, t

time, t = distance, s / speed, v

time, t = 1.1 / 18

time, t = 0.061 s, converting to milliseconds, we have, time, t = 61 ms

6 0
3 years ago
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murzikaleks [220]

One dimension:

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Three dimensions:
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8 0
3 years ago
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