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strojnjashka [21]
4 years ago
11

Which has more gravitational potential energy: a 300 N cat at a height of 6 meters or a 50 N bird at a height of 50 meters

Physics
1 answer:
Zolol [24]4 years ago
7 0

Gravitational Potential energy is given by the formula

U = mgH

so it is product of weight of object and its height

for PE of cat weight is given as 300 N at height 6 m

U_1 = 300 \times 6 = 1800 J

on other side we will have a bird of 50 N weight with height 50 m

U_2 = 50 \times 50 = 2500 J

now here we can see that it depends on the product of weight and height both

so here PE of bird will be more than the PE of Cat

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A simple pendulum with a length of 2.23 m and a mass of 6.74 kg is given an initial speed of 2.06 m/s at its equi- librium posit
solniwko [45]

Answer:

a)   T = 2.997 s

b)   K = 14.3 J

c)   φ = 0.444 rad

Explanation:

a) Determine its period

  The pendulum simple’s period is:

 

  T = 2π\sqrt{\frac{l}{g} }

        Where l: Pendulum’s length

                    g = 9.8 m/s2

  T = 2π\sqrt{\frac{2.23}{9.8} }

  T = 2.997 s

b) Total energy

  Initially his total energy is kinetic

  K = \frac{mv^{2} }{2}

  K = \frac{(6.74)(2.06)^{2} }{2}

  K = 14.3 J

c) Maximum angular displacement

  φ = cos^{-1}(1-\frac{E}{mgl} )

  φ = cos^{-1}(1-\frac{14.3}{(6.74)(9.8)(2.23)} )

  φ = 0.444 rad

4 0
3 years ago
Answer the question below
Ivan

Answer:

the the right because opposites attract to each other

6 0
3 years ago
A large fake cookie sliding on a horizontal surface is attached to one end of a horizontal spring with spring constant k = 375 N
spayn [35]

Answer:

The conservation of energy should be used to answer this question.

a)

At the position where the spring is unstretched, the elastic potential energy of the spring is zero.

K_1 + U_1 - W_f = K_2 +U_2\\K_1 - W_f = U_2

since U_1 and K_2 is equal to zero.

W_f = F_fx\\\\U_2 = \frac{1}{2}kx^2\\\\19 - (10)x = \frac{1}{2}(375)x^2\\\\375x^2 + 20x - 38 = 0

The roots of this quadratic equation can be solved by using discriminant.

\Delta = b^2 - 4ac\\x_{1,2} = \frac{-b \pm \sqrt{\Delta}}{2a}

x_1 = -0.346\\x_2 = 0.292

We should use the positive root, so

x = 0.292 m.

b)

We should use energy conservation between the point where the spring is momentarily at rest, and the point where the spring is unstretched.

K_2 + U_2 - W_f = K_3 + U_3\\U_2 - W_f = K_3

since the kinetic energy at point 2 and the potential energy at point 3 is equal to zero.

\frac{1}{2}kx^2 - F_fx = K_3\\K_3 = 15.987 - 2.92 = 13.067 J

Explanation:

In questions with springs, the important thing is to figure out the points where kinetic or potential energy terms would be zero. When the spring is unstretched, the elastic potential energy is zero. And when the spring is at rest, naturally the kinetic energy is equal to zero.

In part b) the cookie slides back to its original position, so the distance traveled, x, is equal to the distance in part a). The frictional force is constant in the system, so it is quite simple to solve part b) after solving part a).

8 0
3 years ago
Init. A
Gekata [30.6K]

Answer:

v = 1/3 m / s = 0.333 m / s

in the direction of the truck

Explanation:

The average speed is defined by the variation of the position between the time spent

           v = Δx / Δt

since the position is a vector we must add using vectors, we will assume that the displacement to the right is positive, the total displacement is

           Δx = 20 - 15 +20

           Δx = 25 m

therefore we calculate

         v = 25/75

         v = 1/3 m / s = 0.333 m / s

in the direction of the truck

7 0
3 years ago
In 1929, American astronomer Edwin Hubble discovered that distant galaxies were moving away from us. He found that light from di
Novay_Z [31]

Answer:

it is the Hubble law

Explanation:

Hubble's law, also known as the Hubble–Lemaître law, is the observation in physical cosmology that galaxies are moving away from the Earth at speeds proportional to their distance. In other words, the farther they are the faster they are moving away from Earth.

7 0
3 years ago
Read 2 more answers
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