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Hitman42 [59]
3 years ago
6

Anyone good with scientific notations? I sure am not

Physics
2 answers:
defon3 years ago
7 0
B is the answer that I know of.
algol133 years ago
5 0
I'm pretty sure it is b but don't take my word for it
You might be interested in
Please help with both questions thank you!
Katen [24]

I think is:

(4)Inner core

(4)different Kingdome different species

hope this help :)

3 0
2 years ago
2.What is the weight of an object that has a mass of 5 kg?<br>​
Artemon [7]

Answer:

5 kg

or 11 lbs

Explanation:

4 0
3 years ago
A block of mass m=9.0 kg and speed V and is behind a block of mass M= 27 kg and speed of .50 m/s. The surface is frictionless, a
sammy [17]

Answer:

2.06 m/s

Explanation:

From the law of conservation of linear momentum, the sum of momentum before and after collision are equal. Considering this case where we have frictionless surface, no momentum is lost in the process.

Momentum before collision

Momentum is given by p=mv where m and v represent mass. The initial sum of momentum will be 9v+(27*0.5)=9v+13.5

Momentum after collision

The momentum after collision will be given by (9+27)*0.9=32.4

Relating the two then 9v+13.5=32.4

9v=18.5

V=2.055555555555555555555555555555555555555 m/s

Rounded off, v is approximately 2.06 m/s

5 0
3 years ago
2. What is one way that science helps shape society?
zhuklara [117]

Answer:Science is valued by society because the application of scientific knowledge helps to satisfy many basic human needs and improve living standards. Finding a cure for cancer and a clean form of energy are just two topical examples.

Explanation:

4 0
3 years ago
The resistance, R, of a wire varies directly as its length and inversely as the square of its diameter. If the resistance of a w
lbvjy [14]

R is proportional to the length of the wire:

R ∝ length

R is also proportional to the inverse square of the diameter:

R ∝ 1/diameter²

The resistance of a wire 2700ft long with a diameter of 0.26in is 9850Ω. Now let's change the shape of the wire, adding and subtracting material as we go along, such that the wire is now 2800ft and has a diameter of 0.1in.

Calculate the scale factor due to the changed length:

k₁ = 2800/2700 = 1.037

Scale factor due to changed diameter:

k₂ = 1/(0.1/0.26)² = 6.76

Multiply the original resistance by these factors to get the new resistance:

R = R₀k₁k₂

R₀ = 9850Ω, k₁ = 1.037, k₂ = 6.76

R = 9850(1.037)(6.76)

R = 69049.682Ω

Round to the nearest hundredth:

R = 69049.68Ω

8 0
3 years ago
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