$A = \frac{\alpha*r^{2} }{2} \\where:\\A= area = 64[in^{2}]\\r = radius = 8[in]\\\\\alpha = angle[rad]therefore\\\alpha =\frac{2*A}{r^{2} } \\\alpha =\frac{2*64}{8^{2} } \\\alpha =2[rad]$

Now using the following equation we can calculate the arc length

$L=\alpha *r\\L=2*8\\L=16[in]$

5 0

3 years ago

A light-rail commuter train speeds up at a rate of 1.65 m/s 2 and takes 19.0 s to reach its top speed. How far down the tracks d

Margarita [4]

Answer:

297.8 m

Explanation:

We are given that

Acceleration= $a=1.65m/s^2$

Time,t=19 s

We have to find the distance covered by the train when it reach its top speed if starting from rest.

Initial speed=u=0

$s=ut+\frac{1}{2}at^2$

Using the formula

$s=0(19)+\frac{1}{2}\times 1.65(19)^2$

$s=297.8 m$

Hence, the train covered 297.8 m when the train go to reach its top speed if starting from rest.

7 0

3 years ago

Hii please help i’ll give brainliest if you give a correct answer please please hurry!!!

maw [93]

It should be B: They are equal and act in opposite directions.

4 0

3 years ago

Read 2 more answers