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Hitman42 [59]
3 years ago
6

Anyone good with scientific notations? I sure am not

Physics
2 answers:
defon3 years ago
7 0
B is the answer that I know of.
algol133 years ago
5 0
I'm pretty sure it is b but don't take my word for it
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your friend want to know the amont of salt added to her favorite fast food french fries what would you recommend that she do to
Alexeev081 [22]
That nutritional information is usually not posted up on the wall,
but by federal law, it's available on request, to any customer, at
any fast-food place. 

All she has to do is ask to see the manager, and then ask the
manager for the nutritional information booklet. 

She'll get a nice printed booklet that tells the salt content in the
fries, AND the amount of many other substances in ALL the items
sold at that place.

It's the law.  Don't be bashful.
5 0
3 years ago
Spring constant here for 22 cm spring is 50 N per metre 840 if you stretch the spring and when is measured again is 32 cm long w
seraphim [82]
K= fx => f = k/x => 50N/100cm / 10 cm = 5/10= 0.5 N
3 0
3 years ago
A 150 kg object takes 90 seconds to travel a 2500 meter straight path. It begins the trip traveling 120 meters per second and de
Nana76 [90]

The acceleration is -1.111 m/s²

Explanation:

In this case acceleration is calculated as change in velocity divided by time.

Change in velocity is 20m/s-120 m/s = -100 m/s

Time is 1.5 minutes------change it to seconds by multiplying 1.5 by 60 seconds

Acceleration will be : -100 m/s / (1.5*60) = -1.111 m/s²

Learn More

To calculate acceleration :brainly.com/question/856414

Keywords : object, travel, straight path, velocity, decelerate, acceleration

#LearnwithBrainly

3 0
4 years ago
A charge q = 3 × 10-6 C of mass m = 2 × 10-6 kg, and speed v = 5 × 106 m/s enters a uniform magnetic field. The mass experiences
NeX [460]

Answer:

Magnetic field, B = 0.004 mT

Explanation:

It is given that,

Charge, q=3\times 10^{-6}\ C

Mass of charge particle, m=2\times 10^{-6}\ C

Speed, v=5\times 10^{6}\ m/s

Acceleration, a=3\times 10^{4}\ m/s^2

We need to find the minimum magnetic field that would produce such an acceleration. So,

ma=qvB\ sin\theta

For minimum magnetic field,

ma=qvB

B=\dfrac{ma}{qv}

B=\dfrac{2\times 10^{-6}\ C\times 3\times 10^{4}\ m/s^2}{3\times 10^{-6}\ C\times 5\times 10^{6}\ m/s}

B = 0.004 T

or

B = 4 mT

So, the magnetic field produce such an acceleration at 4 mT. Hence, this is the required solution.

4 0
3 years ago
WILL GIVE BRAINLIEST!!!
kumpel [21]

Answer:

72.53 mi/hr

Explanation:

From the question given above, the following data were obtained:

Vertical distance i.e Height (h) = 8.26 m

Horizontal distance (s) = 42.1 m

Horizontal velocity (u) =?

Next, we shall determine the time taken for the car to get to the ground.

This can be obtained as follow:

Height (h) = 8.26 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

8.26 = ½ × 9.8 × t²

8.26 = 4.9 × t²

Divide both side by 4.9

t² = 8.26 / 4.9

Take the square root of both side by

t = √(8.26 / 4.9)

t = 1.3 s

Next, we shall determine the horizontal velocity of the car. This can be obtained as follow:

Horizontal distance (s) = 42.1 m

Time (t) = 1.3 s

Horizontal velocity (u) =?

s = ut

42.1 = u × 1.3

Divide both side by 1.3

u = 42.1 / 1.3

u = 32.38 m/s

Finally, we shall convert 32.38 m/s to miles per hour (mi/hr). This can be obtained as follow:

1 m/s = 2.24 mi/hr

Therefore,

32.38 m/s = 32.38 m/s × 2.24 mi/hr / 1 m/s

32.38 m/s = 72.53 mi/hr

Thus, the car was moving at a speed of

72.53 mi/hr.

7 0
3 years ago
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