<h3><u>Answer;</u></h3>
a) 5.00 x 10^8 J
<h3><u>Explanation;</u></h3>
The work done to move the sailboat is calculated through the equation;
W = F x d
where F is force and d is the distance.
Substituting the known values from the given above,
W = (5.00 x 10⁴ N)(10 km)(1000 m/ 1km)
= 5.00 x 10⁸ J
Thus, the work done is <u>5.00 x 10⁸Joules</u>
Answer:resultant vector R = (0, 3)
Explanation: vector A = (3, 0)
vector B =(-3, 3)
Vectors are added such that those in same directions are added together. The resultant vector R is the given by R = (3-3, 0+3)
= (0, 3)
Answer:
hence option A is correct
Explanation:
heat required from -9°C to 0°C ice = mass × specific heat of ice ×change in temperature
heat required from -9°C to 0°C ice = 7×2100×9 =132300 J =0.1323 MJ
( HERE SPECIFIC HEAT OF ICE IS A CONSTANT VALUE OF 2100
J/(kg °C )
heat required from 0°C ice to 0°C water = mass× specific heat of fusion of ice
= 7×3.36×10^5
= 2.352 × 10^6 J
= 2.352 MJ
TOTAL HEAT ENERGY REQUIRED = 0.1323 MJ +2.352 MJ
= 2.4843 MJ
hence option A is correct
YES, ELECTRICITY CONCERNS ENERGY WHICH IS USED AS A FUEL . IN MODERN DAY TECH, MOST MACHINES USE ELECTRICITY AS A FUEL SUCH AS THE ELECTRONIC TRAIN IN TOKYO, JAPAN.
Vf = Vi + at
Vf = 0 + 5.4•28
= 151.2m/s..
not sure if its right
