Answer:
deez n u t s
Step-by-step explanation:
Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
━═━═━═━═━═━═━═━═━━═━═━═━═━═━
4.41 ounces. 1.5 +2.25 + .66=4.41. You just multiply the faction by the number and add it all up.
Answer:
11/2
Step-by-step explanation:
when,
Now substitute the value we get,