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Lemur [1.5K]
4 years ago
9

A toy projectile is fired from the ground vertically upward with an initial velocity of 26.5 m/s. The project arrives at its max

imum altitude in 2.7s.
What is the velocity of the projectile when it hits the ground? How?
Physics
1 answer:
elena-14-01-66 [18.8K]4 years ago
7 0
<span>26.5 m/s Ignoring air resistance, the projectile will have an initial kinetic energy expressed by E = 0.5 M V^2 and as the projectile travels upward, it's kinetic energy will decrease while it's potential gravitational kinetic energy increases such that the sum of both is constant. Then once it starts to descent, the potential energy is converted back into kinetic energy. And when it finally reaches the ground, it's kinetic energy will exactly match the original kinetic energy it had initially. And the only way it can match since the mass never changes is for it to have the same velocity as it had when it was first fired.</span>
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Which of the following is a correct formula of speed
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Answer:s= d/t

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3 years ago
A tank is full of water. Find the work W required to pump the water out of the spout. (Use 9.8 m/s2 for g. Use 1000 kg/m3 as the
Sergio039 [100]

Answer:

W = 1.06 MJ

Explanation:

- We will use differential calculus to solve this problem.

- Make a differential volume of water in the tank with thickness dx. We see as we traverse up or down the differential volume of water the side length is always constant, hence, its always 8.

- As for the width of the part w we see that it varies as we move up and down the differential element. We will draw a rectangle whose base axis is x and vertical axis is y. we will find the equation of the slant line that comes out to be y = 0.5*x. And the width spans towards both of the sides its going to be 2*y = x.

- Now develop and expression of Force required:

                                             F = p*V*g

                                             F = 1000*(2*0.5*x*8*dx)*g

                                             F = 78480*x*dx

- Now, the work done is given by:

                                             W = F.s

- Where, s is the distance from top of hose to the differential volume:

                                             s = (5 - x)

- We have the work as follows:

                                            dW = 78400*x*(5-x)dx

- Now integrate the following express from 0 to 3 till the tank is empty:

                                           W = 78400*(2.5*x^2 - (1/3)*x^3)

                                           W = 78400*(2.5*3^2 - (1/3)*3^3)

                                           W = 78400*13.5 = 1058400 J

 

5 0
3 years ago
A soccer player carries the ball for a distance of 40.0 m in the direction 42.0° west of south. find the westward component of t
Maksim231197 [3]

Actually what the problem meant about the westward component of the ball’s displacement is the horizontal component of the displacement. To help us better understand the problem, I attached a figure of the situation.

We can see from the figure that to solve for the value of the horizontal component, we have to make use of the sin function. That is:

sin θ = side opposite to the angle / hypotenuse of the triangle

sin 42 = x / 40 m

x = (40 m) sin 42

x = 26.77 m

 

Therefore the ball has a westward displacement of about 26.77 m

3 0
3 years ago
Find the power of a force F~ = (8 N)ˆı + (−4 N) ˆ if the velocity ~v = (−7 m/s)ˆı + (1 m/s) ˆ. Answer in units of W
Vikki [24]

Answer:

P=-60W

Explanation:

From the question we are told that

Force of power F=8Ni+-4Nj

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Generally the equation for power is mathematically represented as

Power=Force *Velocity

P=F *V

Generally the dot product of F and V is mathematically given as

P= \begin{vmatrix}8 & -4\end{vmatrix} .\begin{vmatrix}-7 & 1\end{vmatrix}  =-56-4

P=-60W

6 0
3 years ago
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