Answer:
5 no
Explanation:
actually the 4kg lying on table has no influence
it slides towards 4kg weight hung
as it has excess 2kg force
force=miu × m ×g
the answer to your question would be D.
The terminal speed of the marble is 0.588 m/s.
<h3>Calculation:</h3>
We know that,
F = mg ......(1)
where,
F = force
m = mass
g = acceleration due to gravity
Also,
v = F/k ......(2)
where,
v = terminal speed
k = proportionality constant
Substituting the value of F from equation (1) in equation (2)
v = mg/k .......(3)
Given,
m = 30 g = 0.030 kg
k = 0.500 kg/s
g = 9.8 m/s²
To find,
v =?
Put the values in equation (3)
v = mg/k
v = 0.03(9.8)/ 0.500
= 0.294/0.500
= 0.588 m/s
Hence, the terminal speed of the marble is 0.588 m/s.
Learn more about calculation of force here:
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.
Answer:
No
Explanation:
From the analogy of the problem we are made to know that "a man standing on the earth can exert the same force with his legs as when he is standing on the moon".
This force he is exerting is due to his weight. If he can have the same weight on the earth and moon, therefore:
weight = mass x acceleration due gravity
His mass and acceleration due to gravity on both terrestrial bodies are the same.
So, his jump height will be the same on earth and on the moon.
In summary, we have been shown that his mass and the acceleration due to gravity on both planets are the same, therefore, his weight will also be the same. His jump height will also be same.
Given:
heat generated by John's cooling system, 
= 45 W (1)
If ρ, A, and v corresponds to John's cooling system then let 
be the variables for Mike's system then:
Formula use:
Heat generated,
where,
= density
A = area
v = velocity
Solution:
for Mike's cooling system:
= 
⇒ = 
× A × 
= 4.513
A
Using eqn (1) in the above eqn, we get:
= 4.513 × 45 = 203.09 W
