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olga2289 [7]
3 years ago
11

Which function is the same as y=cos(2(x+pi/2))-2

Mathematics
1 answer:
miss Akunina [59]3 years ago
8 0
Y=cos(2x+pi) - 2
y= - cos(2x) - 2
{ Since cos(x+pi) =-cos(x)}
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Write the equation of a circle with center (6,4) that passes through the coordinate (2,1). In your final answer, include all of
kari74 [83]
R^2=(x-6)^2+(y-4)^2

r^2=(6-2)^2+(4-1)^2, r^2=16+9=25

(x-6)^2+(y-4)^2=25
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3 years ago
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Find the degree of the following polynomial:<br> 7xy223 + 8y5 – 3x4 + 4
Vika [28.1K]

Answer:

224

Step-by-step explanation:

polynomial degree:224

leading term:7x^223

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Is (2, 6) a solution to this system of equations?<br> y = -x + 8<br> y = 5x - 4<br> yes<br> no
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Step-by-step explanation:

To see is (2, 6) is a system, we can plug it into the system to check if it gives us true statements:

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2 years ago
Marni and Mikela are playing a color-guessing game. Each player chooses two colors from a list of red (R), blue (B), green (G),
Sladkaya [172]

The answer should be 1/2.

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+{-x2y+[-(x2y-2xy2+y2)+(-xy2-3y2+x2y)]-(10y2-x2y)}
Kay [80]

Answer:

3xy² -  14y²      

Step-by-step explanation:

I hope that this is the problem

   - x²y + [ - (x²y - 2xy² + y²) + (xy² - 3y² + x²y)] - (10y² - x²y)

= - x²y + [ - x²y + 2xy² - y² + xy² - 3y² + x²y] - 10y² + x²y

Now combine like terms in the [  ].

= - x²y  + [ -x²y + x²y + 2xy² + xy² - y² - 3y² ] - 10y² + x²y

= - x²y  + [ 0 + 3xy² - 4y²] - 10y² + x²y

= - x²y + 3xy² - 4y² -10y² + x²y                      Now combine like terms

=   (-x²y + x²y) + 3xy² + (-4y² - 10y²)

=       0 + 3xy² - 14y²

=  3xy² -  14y²       or    y²(3x - 14)

6 0
3 years ago
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