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Answer:
The average force has a magnitude 6524 N due north.
Explanation:
The average net force F = ma where m = mass of car = 1400 kg and a = acceleration.
a = (v - u)/t where u = initial velocity of car = 0 m/s (since it starts from rest)
v = final velocity of car = 27 m/s due north and t = time of motion = 5.8 s
a = (27 m/s - 0 m/s)/5.8 s = 27 m/s ÷ 5.8 s = 4.66 m/s
Since the direction of the velocity change is the direction of the acceleration, the acceleration is 4.66 m/s due north.
The average force, F = ma = 1400 kg × 4.66 m/s = 6524 N
Since the acceleration is due north, the average force takes the direction of the acceleration.
So the direction of the average force is due north
The average force has a magnitude 6524 N due north.
The total is 21. If you use a calculator or count with your fingers it can help make the answer easier so in the end you will get 21 as your total.
Answer:
The answer is given below
Explanation:
Things provided in the statement:
Pressure <em>P1</em> = 120 kPa and <em>P2</em> = 5.6 MP or 5600 kPa
Power, <em>W</em> = 7 kW
Elevation difference = ∆z = 10 m
Mass of flow = m˙
So potential energy changes may be significant
Specific volume of water V= 0.001 m³/kg
Now putting the values in the formula
Power, <em>W </em>= m˙ x V (<em>P1 - P2</em>) + m˙ x g x ∆z
7 = m˙ x 0.001 (5600 - 120 ) + m˙ x 9.8 x 10 x (1 kJ/kg/ 1000 m^2/s^2)
7 = m˙ x 5.48 + m˙ x 0.098
7 = m ˙x 5.38
m˙ = 7/5.38
So mass flow m˙ = 1.301 kJ/s
Answer:
halve the slit separation
Explanation:
As we know that
In YDS experiment, the equation of fringe width is as follows
where,
D denotes the separation in the middle of screen and slits
d denotes the distance in the middle of two slits
And to increase the Δx we have to decrease the d i.e, the distance between the two slits
Hence, the first option is correct
