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omeli [17]
3 years ago
10

Select the correct answer.

Physics
1 answer:
Murrr4er [49]3 years ago
3 0

Answer:

I will choose the answer A

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If an object is projected horizontally from a height of 5 m with an initial velocity of 7 m/s, what is the value of x0?
tatiyna
ANSWER IS D X0=9.8m/s^2
5 0
2 years ago
Refrigerant-134a enters a compressor at 180 kPa as a saturated vapor with a flow rate of 0.35 m3/min and leaves at 900 kPa. The
Alexus [3.1K]

Answer:

52.5°C

Explanation:

The final enthalpy is determined from energy balance where initial enthalpy and specific volume are obtained from A-12 for the given pressure and state

mh1 + W = mh2

h2 = h1 + W/m

h1 + Wα1/V1

242.9 kJ/kg + 2.35.0.11049kJ/ 0.35/60kg

=287.4 kJ/kg

From the final enthalpy and pressure the final temperature is obtained A-13 using interpolation

i.e T2 = T1 + T2 -T1/h2 -h1(h2 - h1)

= 50°C + 60 - 50/295.15 - 284.79

(287.4 - 284.79)°C

= 52.5°C

7 0
3 years ago
A series of optical telescopes produced an image that has a resolution of about 0.00350 arc second.
Mila [183]

Answer:

The smallest diameter is D =122 \ m

Explanation:

From the question we are told that

       The resolution of the telescope is \theta  =  0.00350 \ arc \ second

           The wavelength is  \lambda = 1.70 \mu m = 1.70 *10^{-6} \ m

From the question we are told that

        1 arc \ sec = \frac{1}{3600^o}

So      0.00350 \ arc \ second = x

Therefore

             x =  0.00350  *  \frac{1}{3600 }

              x = ( 9.722*10^{-7} )^o

Now  1^o  =  \frac{\pi}{180}

   So  (9.722*10^{-7})^o =  \theta

  =>    \theta  =  (9.722*10^{-7}) * \frac{\pi}{180}

           \theta  =  1.69*10^{-8} rad

The smallest diameter is mathematically represented  as

          D = \frac{1.22 \lambda }{\theta  }

substituting values

           D = \frac{1.22 * 1.7 *10^{-6}} {1.69 *10^{-8}  }

           D =122 \ m

   

6 0
3 years ago
A block of mass M slides down a frictionless plane inclined at an angle (theta) with the horizontal. The normal reaction force e
WINSTONCH [101]

Answer: N = Mgcos(theta)

Therefore, the Normal reaction force is equal to Mgcos(theta)

Explanation:

See attached for a sketch.

From the attachment.

.

N = normal reaction force on block

W = weight of the block

theta = angle of the inclined plane to the horizontal

From the sketch, we can see that

N is equal in magnitude but opposite direction to Wy

N = Wy

And

Wy = Wcos(theta)

Wx = Wsin(theta)

Then,

N = Wy = Wcos(theta)

But W = mass × acceleration due to gravity = mg

N = Mgcos(theta)

Therefore, the Normal reaction force is equal to Mgcos(theta)

7 0
3 years ago
Read 2 more answers
PLZZZZZ HELP ASAP I WILL MARK BRAINIEST FOR WHOEVER HAS THE BEST ANSWER!!!!!! THIS IS MY THIRD TIME PUTING THIS QUESTION UP I DO
ddd [48]

Answer:

Well first for criteria think what would the rover need in order to sustain itself on Venus. And for constraints think of anything that could possibly affect the rover( ex: gasses, active volcanoes)

Explanation:

Criteria: Make the rover self sustainable, and allow the rover to have a mission on Venus( ex: collect rock samples)

Constraints, as I mentioned above gasses, and active volcanoes.

I hope this helps! :)

8 0
2 years ago
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