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Whitepunk [10]
2 years ago
14

The mass of Mars is 6. 42 × 1023 kg. Its moon Phobos is 9378 kilometers away from Mars and has a mass of 1. 06 × 1016 kg. What i

s the gravitational force between Mars and Phobos? 5. 16 × 1015 N 5. 16 × 1021 N 4. 84 × 1022 N 4. 84 × 1025 N.
Physics
1 answer:
statuscvo [17]2 years ago
6 0

The gravitational force between two massive objects is directly proportional to the product of masses. The value of the gravitational force between Mars and Phobos is5. 16 \times  10^2^1 \rm \ N.

<h2></h2><h2>Newton's law of universal gravitation: </h2>

F=G{\dfrac{m_1m_2}{r^2}}

Where,

F = Force

G = Gravitational constant = \bold {6.67 x 10^{-11 }}N.m²/kg²

m_1 = Mass of Mars =  \bold {6. 42 \times  10^{23 }\rm \ kg}

m_2    = Mass of Phobos = \bold {1.06 \times  10^{16 }\rm \ kg}

r = Distance between centers of the masses = 9378 km

Put the values in the formula,

F=\bold {6.67 x 10^{-11 }}{\dfrac{\bold {6. 42 \times  10^{23 }\rm \ kg}\times \bold {1.06 \times  10^{16 }\rm \ kg}}{9378 ^2}}\\\\F= 5. 16 \times  10^2^1 \rm \ N

Therefore, the value of the gravitational force between Mars and Phobos is5. 16 \times  10^2^1 \rm \ N.

Learn more about Newton's law of universal gravitation: brainly.com/question/858421

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Answer:

The value is w= 2*10^{-3} \  rad/s

Explanation:

From the question we are told that

  The diameter of the storm is  d =  10.0 \  km  =  10 000 \  m

   The wind speed is  v  =  10.0 \  m/s

   

Generally the radius is mathematically represented as

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=>  r =  \frac{10000}{2}

=>    r =  5000 \ m

Generally the angular velocity is mathematically represented as  

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=>     w= \frac{10}{5000}

=>     w= 2*10^{-3} \  rad/s

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The conductor is initially electrically neutral, and then a charge q is placed at the center of the hollow space. Suppose the co
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The total charge on the interior of the conductor is zero.

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<h3>Total charge on the interior</h3>

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Thus, the total charge on the interior of the conductor is zero.

<h3>Total charge on the exterior</h3>

The total charge on the exterior of the conductor is calculated as follows;

Q = q + 7q = 8q

Thus, the total charge on the exterior of the conductor is 8q.

Learn more about net charge on interior and exterior of conductors here: brainly.com/question/14653264

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