The source and the observer are moving towards each other. The observer is moving toward the source. The source is moving away from the observer
Answer:
Δp = 0.05 p
Explanation:
The moment is
p = m v
The uncertainty of the moment is
Δp = dp/dm Δm + dp/dv Δv
Like the uncertainty in the mass is zero
Δm = 0
ΔP = m Δv
We divide for the moment
Δp / p = Δv / v
They do not indicate that Δv / v = 0.05
Δp / p = 0.05
Δp = 0.05 p
In the case of a system consisting of two cars
p = m₁ v₁ + m₂ v₂
Δp = dp / dv₁ Δv₁ + dp / dv₂ Δv₂
Δp = m₁ Δv₁ + m₂ Δv₂
Δv₁ / v₁ = 0.05
Δv₁ = 0.05 v₁
Δv₂ / v₂ = 0.05
Δv₂ = 0.05 v₂
We replace
Δp = m₁ 0.05 v₁ + m₂ 0.05 v₂
Δp = 0.05 p
To calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.20 above the ground we can get the root of the quad equation for time are t=-0.24 or t =1.84 taking the t = 1.84, so the equation will be:
x = 15.6cos(30) * 1.86, x = 24.79m
Slow down before entering the curve. Stay close to the outside. Use the gas pedal as you enter the middle of the curve.
