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posledela
3 years ago
9

calculate the period of a wave whose frequency is 5 Hz and whose wavelength is 1 cm give your answer in decimal form

Physics
2 answers:
Pavlova-9 [17]3 years ago
8 0
Period T = 1/f,        where f = frequency = 5 Hz

T =  1/5 = 0.20 s

Period = 0.20 seconds.
trapecia [35]3 years ago
4 0
The period is the reciprocal of frequency.

         Period = 1 / (frequency)  =  1 / 5 per sec = 0.2 second.

The wavelength doesn't matter.
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elena55 [62]

Answer:

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For the second part,

the free body diagram of the car should be as follows:

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The total force should be equal to the centripetal force by Newton's Second Law.

F = ma = \frac{mv^2}{R}\\mg + N = \frac{mv^2}{R}

where N = 0 because we are looking for the case where the car loses contact.

mg = \frac{mv^2}{R}\\v^2 = gR\\v = \sqrt{gR}

Now we know the minimum velocity that the car should have. Using the energy conservation found in the first part, we can calculate the minimum height.

mgh = mg2R + \frac{1}{2}mv^2\\mgh = mg2R + \frac{1}{2}m(gR)\\gh = g2R + \frac{1}{2}gR\\h = 2R + \frac{R}{2}\\h = \frac{5R}{2}

Explanation:

The point that might confuse you in this question is the direction of the normal force at the top of the loop.

We usually use the normal force opposite to the weight. However, normal force is the force that the road exerts on us. Imagine that the car goes through the loop very very fast. Its tires will feel a great amount of normal force, if its velocity is quite high. By the same logic, if its velocity is too low, it might not feel a normal force at all, which means losing contact with the track.

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Harlamova29_29 [7]

Answer:

The relationship between acceleration and time relates to the velocity and how it changes throughout the movement of an object.

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olga_2 [115]

Answer:

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