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REY [17]
3 years ago
5

The diagram shows steps and structures involved in protein production. The arrow labeled X is pointing to

Physics
2 answers:
Doss [256]3 years ago
8 0

Answer:ribosome

Explanation:

damaskus [11]3 years ago
5 0

Answer:

It is a ribosome

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Can someone help me with this I don’t understand how to do this
olga nikolaevna [1]

Answer:

You are doing this wrong. Make sure that if you have 2 rows and on the top it has pounds then on the second bottom row you also have pounds so that they cancel each other out.

Explanation:

4 0
3 years ago
A farmer mated two ducks. They produced three offspring. Two of the offspring were then selected to mate with each other because
cestrela7 [59]

it's called inbreeding


7 0
3 years ago
If you are stopped, then get on a bike and accelerate 2 m/s/s south, what us your final velocity after 3 seconds? Please Explain
olga_2 [115]
Vf = Final velocity.
Vi = initial velocity
a = acceleration. 
t = time

Vf = Vi + at

Vf = 0 + (2 m/s^2)(3s)

Vf = 6 m/s south
4 0
3 years ago
A simple pendulum 2 m long swings through a maximum angle of 30 ? with the vertical.
Alexus [3.1K]
The complete question was calculate the period T assuming the smallest amplitude.
Using the equation;
T = 2 π√(L/g)
Where T is the period in seconds, L is the length of the rod or wire in meters and g is the acceleration due to gravity. 
Hence; T = 2×3.14 × √(2/9.81)
                = 6.28 × 0.4515
                = 2.836 seconds
6 0
3 years ago
A 28 kg mass suspends from a light rope 18 m long & is held to one side by the horizontal force, F, as shown below.
frutty [35]

Answer: 215.15 N

Explanation:

If we draw a free body diagram of the mass we will have the following:

\sum{F_{x}}=-Tcos\theta + F=0 (1)

\sum{F_{y}}=Tsin\theta - mg=0 (2)

Where T is the tension force of the rope, m=28 kg the mass, g=9.8 m/s^{2} the acceleration due gravity and mg is the weight.

On the other hand, we can calculate \theta as follows:

cos\theta=\frac{s}{l}

\theta=cos^{-1}(\frac{s}{l})

Where s=11.1 m and l=18 m

\theta=cos^{-1}(\frac{11.1 m}{18 m})

\theta=51.9\° (3)

Now, we firstly need to find T from (2):

T=\frac{mg}{sin\theta} (4)

T=\frac{(28 kg)(9.8 m/s^{2})}{sin(51.9\°)}

T=348.69 N (5)

Substituting (5) in (1):

F=Tcos\theta (6)

F=348.69 N cos(51.9\°)

Finally:

F=215.15 N

8 0
3 years ago
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