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pashok25 [27]
2 years ago
14

A uniform disk with a 25 cm radius swings without friction about a nail through the rim. If it is released from rest from a posi

tion with the center level with the nail, then what is its angular velocity as it swings through the point where the center is below the na
Physics
1 answer:
ValentinkaMS [17]2 years ago
6 0

Answer:

Explanation:

During the swing , the center of mass will go down due to which disc will lose potential energy which will be converted into rotational kinetic energy

mgh = 1/2 I ω² where m is mass of the disc , h is height by which c.m goes down which will be equal to radius of disc , I is moment of inertia of disc about the nail at rim , ω is angular velocity .

mgr  = 1/2 x ( 1/2 m r²+ mr²) x ω²

gr  = 1/2 x 1/2  r² x ω² + 1/2r² x ω²

g = 1 / 4 x ω² r + 1 / 2 x ω² r

g = 3  x ω² r/ 4

ω² = 4g /3 r

= 4 x 9.8 /  3 x  .25

= 52.26

ω = 7.23  rad / s .

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Read 2 more answers
Unpolarized light with an intensity of 655 W / m2 is incident on a polarizer with an unknown axis. The light then passes through
Norma-Jean [14]

Answer:

1.\theta=29.84^{0}

2.\theta=60.15^{0}

Explanation:

Polarizes axis can create two possible angles with the vertical.

first we have to find the intensity of  first polarizer

which is given as

I=\frac{I_{0} }{2}

I= \frac{655\frac{W}{M^{2} } }{2}

I=327.5\frac{W}{m^{2} }

For a smaller angle for the first polarizer:

According to Malus Law

I_{2} =I_{1} Cos^{2}(90^{0} - \theta)

I_{2} =I_{1} sin^{2}\theta

\frac{I_{2} }{I_{1} }=Sin^{2}\theta

taking square root on both sides

\sqrt{\frac{163}{327.5} } = sin\theta

\theta=Sin^{-1}(0.4977)

\theta=29.84^{0}

For a larger angle for the first polarizer:

According to Malus Law

I_{2} =I_{1} cos^{2}\theta

\frac{I_{2} }{I_{1} }=Cos^{2}\theta

taking square root on both sides

\sqrt{\frac{163}{327.5} } = cos\theta

\theta=Cos^{-1}(0.4977)

\theta=60.15^{0}

7 0
3 years ago
A person gives a shopping cart an initial push along a horizontal floor to get it moving, and then lets go. The cart travels for
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Answer:

Only a backward force is acting, no forward force.

Explanation:

  • Once released from the initial push, in absence of friction, the shopping cart would continue moving forward at a constant speed forever.
  • As it would move at a constant speed, no net force would be acting on it.
  • So, if it is gradually slowing, there must  be a net force producing an acceleration in a direction opposite to the movement.
  • This force is the kinetic friction force, and is the only force acting on the cart in the horizontal direction.
  • As any friction force, opposes to the relative movement between the cart and the horizontal floor, which means that is directed backward.
  • This is consistent with the direction of the acceleration of the cart.
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3 years ago
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