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3 years ago

Which of the following is an example of a main sequence star

Physics

2 answers:

miss Akunina [59]3 years ago

7 0

I know this question is old but it still needed an answer :-) hope this helps anyone who needs it!

Westkost [7]3 years ago

3 0

The star is the main sequence

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To find the mass defect for uranium-238 several calculations must be made. Which is the calculation that should be made first? A

BaLLatris [955]

mass number of uranium 238 is sum of number of proton and neutrons in it

While atomic number is just number of protons

So total number of protons in it = 92

total number of neutrons in it = 238 - 92 = 146

mass of proton = 1.0073 amu

mass of neutron = 1.0087 amu

now for the calculation of mass of nuclei is given as

$M = zm_p + (A-z)m_n$

$M = 92(1.0073) + 146(1.0087)$

so option B is correct

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4 years ago

Venn diagrams are used for comparing and contrasting topics. The overlapping sections show characteristics that the topics have

tangare [24]

Answer:

Carry energy and follow a pattern

5 0

3 years ago

Read 2 more answers

A 20-N force applied to the handle of a door produces a 44-N output force. What is the AMA of the handle?

Zepler [3.9K]

Method:

44 N / 20 N
AMA = 2.2

4 0

3 years ago

A particle with charge 7.76×10^(−8)C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction.

kodGreya [7K]

Answer:

The z-component of the force is $\= F_z = 0.00141 \ N$

Explanation:

From the question we are told that

The charge on the particle is $q = 7.76 *0^{-8} \ C$

The magnitude of the magnetic field is $B = 0.700\r i \ T$

The velocity of the particle toward the x-direction is $v_x = -1.68*10^{4}\r i \ m/s$

The velocity of the particle toward the y-direction is

$v_y = -2.61*10^{4}\ \r j \ m/s$

The velocity of the particle toward the z-direction is

$v_y = -5.85*10^{4}\ \r k \ m/s$

Generally the force on this particle is mathematically represented as

$\= F = q (\= v X \= B )$

So we have

$\= F = q ( v_x \r i + v_y \r j + v_z \r k ) \ \ X \ ( \= B i)$

$\= F = q (v_y B(-\r k) + v_z B\r j)$

substituting values

$\= F = (7.7 *10^{-8})([ (-2.61*10^{4}) (0.700)](-\r z) + [(5.58*10^{4}) (0.700)]\r y)$

$\= F= 0.00303\ \r j +0.00141\ \r k$

So the z-component of the force is $\= F_z = 0.00141 \ N$

Note : The cross-multiplication template of unit vectors is shown on the first uploaded image ( From Wikibooks ).

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3 years ago

What do crystal of table salt look like?

Pavel [41]

They look like tiny cubes. They are in a cubic form.

6 0

3 years ago