1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
patriot [66]
3 years ago
7

You move to Mars and as a momento from Earth take your Ma-maw's mercury barometer. You place it outside in the Martian atmospher

e and read a very low pressure. Does the pressure reading accurately reflect the atmospheric on the surface of Mars
Physics
1 answer:
oksano4ka [1.4K]3 years ago
8 0

Answer:

Explanation:

No, the reading is not expected to be accurate. This is because Relative to Earth, the air on Mars is extremely thin. The Martian atmosphere is primarily carbon dioxide with a much lower surface pressure, and Mars does not have oceans and an Earthlike hydrological cycle so latent heat release is not as important as it is for Earth.

You might be interested in
What is the slope of (0,0)(4,200)
Kruka [31]

Answer:

.02

Explanation:

X-x/ Y-y= 4-0/200-0 =.02

5 0
3 years ago
Read 2 more answers
Weight and mass are interchangeable terms. True or False
Nonamiya [84]
It's false. Mass is a way of measuring how much matter an object contains, where as weight measures how hard gravity is pulling on an object. While on earth, these are typically interchangeable. However, if you were to go to Mars, your mass would stay the same, but the weight will be different. This is because you still contain the same amount of matter, but the gravity's pull will be different because the moon has a different gravitational pull than the earth. Hope this helps!
5 0
3 years ago
Read 2 more answers
Freeeeeeeee poinnttttsssss
RUDIKE [14]

Answer:

k

Explanation:

umm really

5 0
3 years ago
A car slams on its brakes, coming to a complete stop in 4.0 s. The car was traveling south at 60.0 mph. Calculate the accelerati
emmainna [20.7K]
Acceleration = ms^(-1)
= 60/4
=15 ms with the power of -1
4 0
3 years ago
Read 2 more answers
A rock with a mass of 6.1 kg falls 1.5 m. What potential energy does it have before the fall?
denpristay [2]

89.67J

Explanation:

Given parameters:

Mass of rock = 6.1kg

Height of fall = 1.5m

Unknown:

Potential energy = ?

Solution:

The potential energy is the energy at rest or due to the position of a body.

Potential energy is mathematically expressed as;

  Potential energy = mgh

m is the mass of the rock

g is the acceleration due to gravity of the rock

h is the height of the rock

   Potential energy = 6.1 x 9.8 x 1.5 = 89.67J

learn more:

Potential energy brainly.com/question/10770261

#learnwithBrainly

6 0
3 years ago
Other questions:
  • 24x515,382xcos(555) what is the answer?
    13·1 answer
  • Una rapidez de 7 mm/us es igual a:<br><br> A) 7000m/s<br> B) 70 m/s<br> C) 7 m/s<br> D) 0.07 m/s
    13·1 answer
  • Considering the factors that affect gravitational pull, in which location would the gravitational pull from the earth be SMALLES
    11·2 answers
  • Because the droplets are conductors, a droplet's positive and negative charges will separate while the droplet is in the region
    7·1 answer
  • A balloonist happens to drop his metal ballpoint pen from his balloon as he is taking notes on his flight. Because his pen has a
    15·1 answer
  • What is an example of convection? A. A heater in a fish tank warming the water at the bottom of the tank B. Batteries in a flash
    5·2 answers
  • When looking at the Impulse of an object during a collision, we often use "average force"? When an object hits something, is the
    8·1 answer
  • Calculate, for the judge, how fast you were going in miles per hour when you ran the red light because it appeared Doppler-shift
    6·1 answer
  • Natural Resources Question 5
    15·1 answer
  • for every 120 joules of energy input a car waste 85 joules, find the useful energy output of the car?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!