Answer:
-384.22N
Explanation:
From Coulomb's law;
F= Kq1q2/r^2
Where;
K= constant of Coulomb's law = 9 ×10^9 Nm^2C-2
q1 and q2 = magnitudes of the both charges
r= distance of separation
F= 9 ×10^9 × −7.97×10^−6 × 6.91×10^−6/(0.0359)^2
F= -495.65 × 10^-3/ 1.29 × 10^-3
F= -384.22N
Answer:
Explanation:
A ) Distance between two adjacent anti-node will be equal to distance between two adjacent nodes . So the required distance is 15 cm .
B ) wave-length, amplitude, and speed of the two traveling waves that form this pattern are as follows
wave length = same as wave length of wave pattern formed. so it is 30 cm
amplitude = 1/2 the amplitude of wave pattern formed so it is .850 / 2 = .425 cm
Speed = frequency x wavelength ( frequency = 1 / time period )
= 1 / .075) x 30 cm
400 cm / m
C ) maximum speed
= ω A
= (2π / T) x A
= 2 X 3.14 x .85 / .075 cm / s
= 71.17 cm / s
minimum speed is zero.
D ) The shortest distance along the string between a node and an antinode
= Wavelength / 4
= 30 / 4
= 7.5 cm
Answer:
Total energy of the object = mgh. As it falls, its potential energy will change into kinetic energy. If v is the velocity of the object at a given instant, the kinetic energy = 1/2mv2.
Explanation:
The skateboard that has the greatest impulse is Skateboard C (Impulse = 25.74 Ns)
From the question,
We are to determine which skateboard has the greatest impulse. To do this, we will calculate the impulse of each skate board.
Impulse can be calculated by using the formula
I = Ft
Where I is the impulse
F is the force
and t is the time
Force = 33 N
Time = 0. 12 s
∴ Impulse = 33 × 0.12
Impulse = 3.96 Ns
Force = 33 N
Time = 0. 57 s
∴ Impulse = 33 × 0.57
Impulse = 18.81 Ns
Force = 33 N
Time = 0. 78 s
∴ Impulse = 33 × 0.78
Impulse = 25.74 Ns
Hence, the skateboard that has the greatest impulse is Skateboard C (Impulse = 25.74 Ns)
Learn more here: brainly.com/question/21840495