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Shalnov [3]
3 years ago
15

A treasure map instructs you to walk (25.0+A) m south, followed by (18.0+B) m east, then 64.5 m north, and finally 28.5 m east.

Determine the magnitude of your total displacement, if you follow these instructions. Calculate the answer in meters (m) and rounded to three significant figures.

Physics
1 answer:
adelina 88 [10]3 years ago
3 0

Answer:

Explanation:

Check attachment for solutions

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A disk of mass m and moment of inertia of I is spinning freely at 6.00 rad/s when a second identical disk, initially not spinnin
Nadusha1986 [10]

Answer:

The angular speed of the new system is 3\,\frac{rad}{s}.

Explanation:

Due to the absence of external forces between both disks, the Principle of Angular Momentum Conservation is observed. Since axes of rotation of each disk coincide with each other, the principle can be simplified into its scalar form. The magnitude of the Angular Momentum is equal to the product of the moment of inertial and angular speed. When both disks begin to rotate, moment of inertia is doubled and angular speed halved. That is:

I\cdot \omega_{o} = 2\cdot I \cdot \omega_{f}

Where:

I - Moment of inertia of a disk, measured in kilogram-square meter.

\omega_{o} - Initial angular speed, measured in radians per second.

\omega_{f} - Final angular speed, measured in radians per second.

This relationship is simplified and final angular speed can be determined in terms of initial angular speed:

\omega_{f} = \frac{1}{2}\cdot \omega_{o}

Given that \omega_{o} = 6\,\frac{rad}{s}, the angular speed of the new system is:

\omega_{f} = \frac{1}{2}\cdot \left(6\,\frac{rad}{s} \right)

\omega_{f} = 3\,\frac{rad}{s}

The angular speed of the new system is 3\,\frac{rad}{s}.

6 0
2 years ago
Find the magnitude of the average force ⟨Fx⟩⟨Fx⟩ in the x direction that the particle exerts on the right-hand wall of the conta
hodyreva [135]

Answer:

See explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

The attached file has a detailed solution of the given problem.

4 0
3 years ago
A balloon filled with helium has a small hole on the right side of the balloon. How would Pascal explain why the entire balloon
Morgarella [4.7K]

Answer:

delete this answer please.

4 0
2 years ago
A 150-kg object takes 1.5 minutes to travel a 2,500-meter straight path. It begins the trip traveling 120 m/s and decelerates to
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I believe it is -1.11 m/s^2. I will let you know if its correct
7 0
3 years ago
Read 2 more answers
A rock is thrown off a 50.0 m high cliff. How fast must the rock leave the cliff top to land on level ground below, 90 m from th
blagie [28]

Answer:

The rock must leave the cliff at a velocity of 28.2 m/s

Explanation:

The position vector of the rock at a time t can be calculated using the following equation:

r = (x0 + v0x · t, y0 + 1/2 · g · t²)

Where:

r = position vector at time t.

x0 = initial horizontal position.

v0x = initial horizontal velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).

Please, see the attached figure for a graphical description of the problem. Notice that the origin of the frame of reference is located at the edge of the cliff so that x0 and y0 = 0.

When the rock reaches the ground, the position vector will be (see r1 in the figure):

r1 = (90 m, -50 m)

Then, using the equation of the vector position written above:

90 m = x0 + v0x · t

-50 m = y0 + 1/2 · g · t²

Since x0 and y0 = 0:

90 m = v0x · t

-50 m = 1/2 · g · t²

Let´s use the equation of the y-component of the vector r1 to find the time it takes the rock to reach the ground and with that time we can calculate v0x:

-50 m = 1/2 · g · t²

-50 m = -1/2 · 9.81 m/s² · t²

-50 m / -1/2 · 9.81 m/s² = t²

t = 3.19 s

Now, using the equation of the x-component of r1:

90 m = v0x · t

90 m = v0x · 3.19 s

v0x = 90 m / 3.19 s

v0x = 28.2 m/s

8 0
3 years ago
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