What force must be applied to the end of a rod along the x-axis of length 2.25 m in order to produce a torque on the rod about t
1 answer:
Answer:
<h2>4.9N approx.</h2>Explanation:
Step one:
given data
length of rod r= 2.25m
Required torque = 11 Nm
Required
The force needed to produce a torque of 11Nm
Step two:
<em>"By definition, Torque is the twisting force that tends to cause rotation. </em>
<em>The point where the object rotates is known as the axis of rotation."</em>
Mathematically,
= torque
r = radius
F = force
= angle between F and the lever arm
in this case is zero
substituting we have
F=11/2.25
F=4.88N
F=4.9N approx.
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