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Lady bird [3.3K]

3 years ago

8

What force must be applied to the end of a rod along the x-axis of length 2.25 m in order to produce a torque on the rod about t

he origin of 11 z-hat N·m? Choose among the available options below. x,y,z,-z

1 answer:

4vir4ik [10]3 years ago

7 0

Answer:

<h2>4.9N approx.</h2>

Explanation:

Step one:

given data

length of rod r= 2.25m

Required torque = 11 Nm

Required

The force needed to produce a torque of 11Nm

Step two:

<em>"By definition, Torque is the twisting force that tends to cause rotation. </em>

<em>The point where the object rotates is known as the axis of rotation."</em>

Mathematically,

$\tau = rF\sin\theta$

$\tau$ = torque

r = radius

F = force

$\theta$ = angle between F and the lever arm

in this case is zero

$\tau = rF\\\\F=\tau/r$

substituting we have

F=11/2.25

F=4.88N

F=4.9N approx.

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