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dezoksy [38]
3 years ago
14

A sample of oxygen gas occupies a volume of 250 mL at .8 atm of pressure. What volume will it occupy at 1.2 atm of pressure?

Chemistry
1 answer:
musickatia [10]3 years ago
7 0
167 mL

P1V1 = P2V2
P1 = .8 atm
V1 = 250 mL
P2 = 1.2 atm

Solve for V2 —> V2 = P1V1/P2

V2 = (0.8 atm)(250 mL) / (1.2 atm) = 167 mL
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Answer:

2 Fe(iii)2O3 + 3 C ==> 2 Fe  + 3 CO2

Explanation:

First of all, you have to translate the words into an equation.

Fe(iii)2O3 + C ==> Fe  + CO2

The easiest way to tackle this is to start with the Oxygens and balance them. They must balance by going to the greatest common factor which is 6. So you multiply the molecule by whatever it takes to get the Oxygens to 6

2 Fe(iii)2O3 + C   ==>     Fe  + 3 CO2

Now work on the irons. There 2 on the left and just 1 on the right. So you need to multiply the iron by 2.

2 Fe(iii)2O3 + C ==> 2 Fe  + 3 CO2

Finally it is the turn of the carbons. There are 3 on the right, so you must make the carbon on the left = 3

2 Fe(iii)2O3 + 3 C ==> 2 Fe  + 3 CO2

And you are done.

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See below  

Step-by-step explanation:

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Explanation:

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