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dezoksy [38]
3 years ago
14

A sample of oxygen gas occupies a volume of 250 mL at .8 atm of pressure. What volume will it occupy at 1.2 atm of pressure?

Chemistry
1 answer:
musickatia [10]3 years ago
7 0
167 mL

P1V1 = P2V2
P1 = .8 atm
V1 = 250 mL
P2 = 1.2 atm

Solve for V2 —> V2 = P1V1/P2

V2 = (0.8 atm)(250 mL) / (1.2 atm) = 167 mL
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What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)
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First we have to calculate the moles of Al.

\text{Moles of }Al=\frac{\text{Mass of }Al}{\text{Molar mass of }Al}

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From the reaction we conclude that,

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Therefore, the volume of O_2 consumed are, 0.75\times 2\times 22.4 L.

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