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myrzilka [38]
3 years ago
8

Which two elements have properties that are the most similar?

Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0

Answer:

The answer to your question is letter b) He and Ne

Explanation:

Elements that have similar properties are placed in the same group in the periodic table.

So

A C and F  These elements do not have similar properties because C is in group 4A and F is in group 7A. This is not the right answer.

B He and Ne  These elements have similar properties becase they are in the same group (8A).

C Al and Si  These elements do not have similar properties because Al is in group 3A and Si is in group 4A. This is not the right answer.

D N and S These elements do not have similar properties because N is in group 5A and S is in group 6A. This is not the right answer.

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6. Which of the following labels for the picture below is correct? a) Solute + solvent = solution b) Solvent + solute = saturati
SVETLANKA909090 [29]

Answer:

answer is a since solute dissolve a solvent to give a solution

4 0
3 years ago
A mixture of methanol and methyl acetate contains 15.0 wt% methanol.
Usimov [2.4K]

The mixture flow rate in lbm/h = 117.65 lbm/h

<h3>Further explanation</h3>

Given

15.0 wt% methanol

The flow rate of the methyl acetate :100 lbm/h

Required

the mixture flow rate in lbm/h

Solution

mass of methanol(CH₃OH, Mw= 32 kg/kmol) in mixture :

\tt 15\%\times 200~kg=30~kg\\\\mol=\dfrac{mass}{MW}=\dfrac{30~kg}{32~kg/kmol}=0.9375~kmol

mass of the methyl acetate(C₃H₆O₂,MW=74 kg/kmol,85% wt) in 200 kg :

\tt 85\%\times 200=170~kg\\\\mol=\dfrac{170}{74}=2.297~kmol

Flow rate of the methyl acetate in the mixture is to be 100 lbm/h.

1 kg mixture = 0.85 .methyl acetate

So flow rate for mixture :

\tt \dfrac{1~kg~mixture}{0.85~methyl~acetat}\times 100~lbm/h=117.65~lbm/h

5 0
3 years ago
What is the Na+ concentration in each of the following solutions:
iren [92.7K]

Sodium Sulfate = Na2(SO4) meaning there are two ions of Na+ in one mole of Sodium Sulfate the M stands for Molarity, defined as Molarity = (moles of solute)/(Liters of solution), So if the Na2SO4 solution is 3.65M that means one Liter of has 3.65 moles of Na2SO4, the stoichiometry of Na2SO4 shows that there would be two Na+ ions in solution for every one Na2SO4.

Therefore if 3.65 moles of Na2SO4 was to dissolve, it would produce 7.3 moles of Na+, and since this is still a theoretical solution, we can assume 1 L of solution.

Finally we find [Na+] = 2*3.65 = 7.3M

Use the same logic for parts b and c




5 0
3 years ago
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