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3 years ago

Please Answer These Questions I Really Need Help Please answer these questions

1 answer:

wel3 years ago

8 0

1. Onion cells have thick rectangular walls.
2. Both are tropospheres, the lobster and fungi have the same outer shell.
3. A bat is a mammal--it has fur, lactates and is warm-blooded. Mammals are vertebrates. Vertebrates have a dorsal nerve cord protected by bony or cartilaginous vertebrae. Arthropods are invertebrates--they do not have vertebrae. They are a specific kind of invertebrate with a jointed exoskeleton.
4, 5, 6, 7 - Sorry don't know these answers to these questions

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The2 archer uses a force of 120 N. The force acts on an area of 0.5 cm2 on the archer's fingers. . Calculate the pressure on the

Mkey [24]

Answer:

Pressure = 24000 N/m²

Explanation:

Given the following data;

Force = 120N

Area = 0.5cm² to meters = 0.5/100 = 0.005 m²

To find the pressure;

Pressure= force/area

Pressure= 120/0.005

Pressure = 24000 N/m²

Therefore, the pressure on the archer's fingers is 24000 Newton per meters square.

4 0

4 years ago

Plz help brainliest plzzzzzzzzzzzzzzzzz!!!!!!!!!!!!!!

Likurg_2 [28]

Answer:

Explanation:

8 0

3 years ago

A skier has an acceleration of 2.5 m/s2. How long does it take her to come to a complete stop from a speed of 18 m/s? A. 3.4 s B

noname [10]

The question is defective. If her acceleration is 2.5 m/s/s, then her speed is 2.5 m FASTER each second, and she will never stop.

6 0

3 years ago

the gasoline in a car does 40000 j of work on a car and generates a constant force of 20 n. how far did the car go?

NikAS [45]

   Work = (force) x (distance)

   40,000 J = (20 N) x (distance)

   Distance = (40,000 J) / (20 N)

=    2,000 meters

= 2 kilometers.

(20 N is not a huge force when it's being used to move a car.
It's only about 4.5 pounds.)

8 0

3 years ago

Robin fired a bullet of mass 100 gm from a gun of mass 5 kg. The bullet leaves the gun with a speed of 400 m/s. After penetratin

Marina CMI [18]

(a) the recoil or backward velocity of the gun is 8 m/s.

(b) the bullet cannot completely penetrate the plank.

The given parameters include;

mass of the bullet, m₁ = 100 g = 0.1 kg

mass of the gun, m₂ = 5 kg

initial velocity of the bullet, u₁ = 400 m/s

thickness of the plank, x = 10 cm

To calculate the following:

(a) the backward velocity of the gun

let the backward velocity of the gun = u₂

Apply the principle of conservation of linear momentum.

m₁u₁ + m₂u₂ = 0

m₂u₂ = -m₁u₁

$u_2 = -\frac{m_1u_1}{m_2} \\\\u_2 = - \frac{0.1 \times 400}{5} \\\\u_2 = -8 \ m/s$

Thus, the recoil or backward velocity of the gun is 8 m/s.

(b) Can the bullet penetrate the plank of the wood completely ?

the bullet traveled 4 cm and lost ¹/₃ of u₁

the remaining distance to completely penetrate the plank = 6 cm

the final velocity of the bullet at 4 cm, v = 400 - ¹/₃ x 400 m/s = 266.67 m/s

the acceleration of the bullet is calculated as;

v² = u₁² + 2as

2as = v² - u²

$a = \frac{v^2 -u_1^2}{2s} \\\\a = \frac{(266.67)^2 -(400)^2}{2\times 0.04} = -1.111 \times 10^6 \ m/s^2$

Finally, determine the distance traveled by the bullet when it comes to a complete stop, that is the final velocity = 0

$v_f^2 = v^2 + 2ad\\\\2ad = v_f^2 - v^2\\\\d = \frac{v_f^2 - v^2}{2a} \\\\d = \frac{(0) - (266.67)^2}{2(-1.111\times 10^6)} \\\\d = 0.032 \ m$

d = 3.2 cm

The total distance traveled by the bullet inside the plank = 4 cm + 3.2 cm = 7.2 cm

Therefore, the bullet cannot completely penetrate the plank.

To learn more about linear momentum visit: brainly.com/question/15869303

6 0

3 years ago