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3 years ago

Please Answer These Questions I Really Need Help Please answer these questions

1 answer:

wel3 years ago

8 0

1. Onion cells have thick rectangular walls.
2. Both are tropospheres, the lobster and fungi have the same outer shell.
3. A bat is a mammal--it has fur, lactates and is warm-blooded. Mammals are vertebrates. Vertebrates have a dorsal nerve cord protected by bony or cartilaginous vertebrae. Arthropods are invertebrates--they do not have vertebrae. They are a specific kind of invertebrate with a jointed exoskeleton.
4, 5, 6, 7 - Sorry don't know these answers to these questions

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3 years ago

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3 years ago

Se transmiten ondas transversales en una cuerda tensada orientada sobre el eje x. La función de ondas correspondientes es y= 5.0

TEA [102]

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Explanation:

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3 years ago

An automobile follows a circular road whose radius is 50 m. Let x and y respectively denote the eastern and northern directions,

IceJOKER [234]

Answer:

The automobile is running at speed of 23.806 meters per second.

Explanation:

From Kinematic we remember that acceleration ( $a$ ) can be defined by this ordinary differential equation in terms of distance:

$a = v\cdot \frac{dv}{ds}$ (1)

Where:

$v$ - Speed of the automobile, measured in meters per second.

$s$ - Distance travelled by the automobile, measured in meters.

If we know that $v = 0.5\cdot s - 0.0025\cdot s^{2}$ , then the equation of acceleration is:

$a = (0.5\cdot s - 0.0025\cdot s^{2})\cdot \left(0.5-0.0050\cdot s\right)$

$a = s\cdot (0.5-0.0025\cdot s)\cdot (0.5-0.0050\cdot s)$

$a = s\cdot (0.0025\cdot s - 0.5)\cdot (0.0050\cdot s-0.5)$

But distance covered by the vehicle is defined by the following formula:

$s = \theta \cdot r$ (2)

Where:

$\theta$ - Arc angle, measured in radians.

$r$ - Radius, measured in radians.

Then, we expand (1) by means of this result:

$a = \theta\cdot r \cdot (0.0025\cdot \theta\cdot r -0.5)\cdot (0.0050\cdot \theta \cdot r-0.5)$

$a = \theta\cdot r \cdot (1.25\times 10^{-5}\cdot \theta^{2}\cdot r^{2}-3.75\times 10^{-3}\cdot \theta\cdot r +0.25)$

$a = 1.25\times 10^{-5}\cdot \theta^{3}\cdot r^{3}-3.75\times 10^{-3}\cdot \theta^{2}\cdot r^{2}+0.25\cdot \theta \cdot r$

And finally we get the following third order polynomial:

$1.25\times 10^{-5}\cdot \theta^{3}\cdot r^{3}-3.75\times 10^{-3}\cdot \theta^{2}\cdot r^{2}+0.25\cdot \theta \cdot r - a = 0$ (3)

If we know that $r = 50\,m$ , $a = 0.6\cdot g$ and $g = 9.807\,\frac{m}{s^{2}}$ , then the polynomial becomes into this:

$1.5625\cdot \theta^{3}-9.375\cdot \theta^{2} +12.5\cdot \theta - 5.886 = 0$ (3b)

This polynomial can be solved analytically by Cardano's Method or by numerical methods. The roots of the polynomial are, respectivelly:

$\theta_{1} \approx 4.365\,rad$ , $\theta_{2} \approx 0.818+i\,0.441\,rad$ , $\theta_{3}\approx 0.818 -i\,0.441\,rad$ , $\theta_{4} \approx 1.563\,rad$

Both first and fourth roots are physically reasonable solution, but the latter represents the angle where automobile begins to skid first. Then, the automobile begins to skid at an angle of 1.563 radians relative to x axis.

The distance travelled by the automobile is: ( $r = 50\,m$ , $\theta \approx 1.563\,rad$ )