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sergeinik [125]
3 years ago
5

Severus Snape knows that density of his powder is 3.00 g/cm3 . He also knows he needs 3.00 cm3 of this powder. What mass in gram

s does he require?
Physics
1 answer:
harina [27]3 years ago
8 0

Answer:

He requires 1 gram of mass.

Explanation:

The density is defined as:

\rho = \frac{m}{V}  (1)

Where m is the mass and V is the volume.

Then, m can be isolated from equation 1 in order to determine the mass.

m = \rho \cdot V (2)

m = (3.00g/cm^{3})(3.00cm^{3})  

m = 1g  

Hence, he requires 1 gram of mass.

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A satellite is in a circular orbit about the earth (ME = 5.98 x 10^24 kg). The period of the satellite is 1.26 x 10^4 s. What is
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Answer: V=5839.051m/s  

Explanation:

According to the <u>Third Kepler’s Law</u> of Planetary motion:

T^{2}=\frac{4\pi^{2}}{GM}a^{3}   (1)

Where;:

T=1.26(10)^{4}s is the period of the satellite

G is the Gravitational Constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}

M=5.98(10)^{24}kg is the mass of the Earth

a  is the semimajor axis of the orbit the satllite describes around the Earth (as we know it is a circular orbit, the semimajor axis is equal to the radius of the orbit).

On the other hand, the orbital velocity V is given by:

V=\sqrt{\frac{GM}{a}}   (2)

Now, from (1) we can find a, in order to substitute this value in (2):

a=\sqrt[3]{\frac{T^{2}GM}{4\pi}^{2}}   (3)

a=\sqrt[3]{\frac{(1.26(10)^{4}s)^{2}(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.98(10)^{24}kg)}{4\pi}^{2}}   (4)

a=11705845.57m   (5)

Substituting (5) in (2):

V=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.98(10)^{24}kg)}{11705845.57m}}   (6)

V=5839.051m/s   (7)  This is the speed at which the satellite travels

6 0
3 years ago
What if multiple forces act on an object in equilibrium??
tatuchka [14]
Unless if all forces cancel each other out , the object will no longer be in equilibrium

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Can you pickle a pickle? Like take a cucumber that's already pickled, can you then pickle that pickled cucumber?
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6 0
3 years ago
Read 2 more answers
2. What do pitch and loudness have in common?
DanielleElmas [232]

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2 years ago
A projectile is fired directly upwards at 49.4 m/s. A second projectile is dropped from rest at some higher elevation at the ins
8090 [49]

Answer:

Explanation:

velocity of first projectile after 3 s

v = u - gt

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