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4 years ago

When using the right-hand rule to determine the direction of the magnetic field around a current-carrying wire, the

Physics

2 answers:

Montano1993 [528]4 years ago

7 0

Answer:

The thumb of the right hand must point in the direction of the current.

Explanation:

The right hand rule is used to find the direction of magnetic field around a current-carrying wire. In this rule, it is consider to hold a current carrying wire in your right hand such that the thumb shows the direction of current. The curled finger gives the direction of magnetic field.

For example, if the current points in northward direction, then the direction of magnetic field is in anticlockwise direction.

notsponge [240]4 years ago

6 0

Answer:

Thumb

Explanation:

The direction of the magnetic field can be determined by using the right-hand rule. According to this rule, hold a current carrying wire in your right hand such that the thumb of the right-hand point in the direction of electric current. The curled finger gives the direction of the magnetic field.

Hence, the thumb shows the electric current.

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Which of the following is not a component of a normal experiment?

MaRussiya [10]

Answer:

D. Validity group

Explanation:

A validity group is not necessarily a component of a normal experiment.

A normal experiment is made up of the dependent variables, independent variables, and most times the control group.

The dependent variable is one that relies on the outcome of the effect produced from the experimental design
The independent variable is the one that causes a desired effect under the study.
The control group is a group that does not receive any treatment nor attenuation of the conditions.

4 0

3 years ago

Displacement is which of the following types of quantities?A. vectorB. scalarC. magnitudeD. dimensional

agasfer [191]

Answer: A. vector

Explanation:

Movement is the change of position of a body at a certain time. The body that experiences this change of position is called mobile.

In this sense, the displacement is the distance in a straight line between the initial and final position of this mobile, which differentiates it from the trajectory, which is the path followed by the body in its movement and a scalar magnitude.

Hence, the displacement is a vector.

6 0

3 years ago

Small college has 2523 students in 1994 and 2891 students in 1996 if the enrollment follows a linear growth pattern how many stu

alexandr1967 [171]

Since it is specified that the relationship is linear, you could think of a linear graph for this. The base year would be 1994. The first point is at (0,2523) while the second point is (2,2891). The slope would be

m = (2891 - 2523)/(2-0) = 184

The slope-intercept form is y = mx + b. Let's substitute (0,2523) to the equation such that
2523 = 184(0)+b
b = 2523

Hence, the equation of the linear graph is y = 184x + 2523. Now, at 2006, x = 2006 - 1994 = 12 years.

y = 184(12) + 2523 = 4,731 students

4 0

4 years ago

A circular bird feeder 19.0 cm in radius has rotational inertia 0.130 kg·m2. It's suspended by a thin wire and is spinning slowl

soldi70 [24.7K]

Answer:

N₂=20.05 rpm

Explanation:

Given that

R= 19 cm

I=0.13 kg.m²

N₁ = 24.2 rpm

$\omega_1=\dfrac{2\pi \times 24.2}{60}\ rda/s$

ω₁= 2.5 rad/s

m= 173 g = 0.173 kg

v=1.2 m

Initial angular momentum L₁

L₁ = Iω₁ - m v r ( negative sign because bird coming opposite to motion of the wire motion)

Final linear momentum L₂

L₂= I₂ ω₂

I₂ = I + m r²

The is no any external torque that is why angular momentum will be conserve

L₁ = L₂

Iω₁ - m v r = I₂ ω₂

Iω₁ - m v r = ( I + m r²) ω₂

Now by putting the all values

Iω₁ - m v r = ( I + m r²) ω₂

0.13 x 2.5 - 0.173 x 1.2 x 0.19 = ( 0.13 + 0.173 x 0.19²) ω₂

0.325 - 0.0394 = 0.136 ω₂

ω₂ = 2.1 rad/s

$\omega_2=\dfrac{2\pi \times N_2}{60}$

N₂=20.05 rpm

3 0

3 years ago

maksim [4K]

Answer:

Explanation:

a,f,,and g is correct because it is indicated that object moving forward

4 0

3 years ago