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HACTEHA [7]
3 years ago
7

When using the right-hand rule to determine the direction of the magnetic field around a current-carrying wire, the

Physics
2 answers:
Montano1993 [528]3 years ago
7 0

Answer:

The thumb of the right hand must point in the direction of the current.

Explanation:

The right hand rule is used to find the direction of magnetic field around a current-carrying wire. In this rule, it is consider to hold a current carrying wire in your right hand such that the thumb shows the direction of current. The curled finger gives the direction of magnetic field.

For example, if the current points in northward direction, then the direction of magnetic field is in anticlockwise direction.

notsponge [240]3 years ago
6 0

Answer:

Thumb

Explanation:

The direction of the magnetic field can be determined by using the right-hand rule. According to this rule, hold a current carrying wire in your right hand such that the thumb of the right-hand point in the direction of electric current. The curled finger gives the direction of the magnetic field.

Hence, the thumb shows the electric current.                            

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If a block of wood dropped from a tall building has attained a velocity of 78.4 m/s how long has it been falling
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Gravity adds 9.8 m/s to the speed of a falling object every second.

An object dropped from 'rest' (v = 0) reaches the speed of 78.4 m/s after  falling for (78.4 / 9.8) = <em>8.0 seconds</em> .

<u>Note:</u>

In order to test this, you'd have to drop the object from a really high cell- tower, building, or helicopter.  After falling for 8 seconds and reaching a speed of 78.4 m/s, it has fallen 313.6 meters (1,029 feet) straight down.

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if a bus has a mass of 5000 kg and a velocity of 10 m/s, what must the velocity of a 1500 kg can be to have the same momentum
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The force of attraction between two oppositely charged pith is 5mx 10 to the -6th power newtons. If the charge on the two is 6.7
My name is Ann [436]

Answer:

0.28 m

Explanation:

The following data were obtained from the question:

Force (F) = 5×10¯⁶ N

Charge 1 (q₁) = 6.7×10¯⁹ C

Charge 2 (q₂) = 6.7×10¯⁹ C

Electrical constant (K) = 9×10⁹ Nm²C¯²

Distance apart (r) =?

Thus, the distance between the two charges can be obtained as follow:

F = Kq₁q₂/r²

5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²

5×10¯⁶ = 4.0401×10¯⁷ / r²

Cross multiply

5×10¯⁶ × r² = 4.0401×10¯⁷

Divide both side by 5×10¯⁶

r² = 4.0401×10¯⁷ / 5×10¯⁶

Take the square root of both side

r = √(4.0401×10¯⁷ / 5×10¯⁶)

r = 0.28 m

Therefore, the distance between the two charges is 0.28 m

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3 years ago
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