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HACTEHA [7]
4 years ago
7

When using the right-hand rule to determine the direction of the magnetic field around a current-carrying wire, the

Physics
2 answers:
Montano1993 [528]4 years ago
7 0

Answer:

The thumb of the right hand must point in the direction of the current.

Explanation:

The right hand rule is used to find the direction of magnetic field around a current-carrying wire. In this rule, it is consider to hold a current carrying wire in your right hand such that the thumb shows the direction of current. The curled finger gives the direction of magnetic field.

For example, if the current points in northward direction, then the direction of magnetic field is in anticlockwise direction.

notsponge [240]4 years ago
6 0

Answer:

Thumb

Explanation:

The direction of the magnetic field can be determined by using the right-hand rule. According to this rule, hold a current carrying wire in your right hand such that the thumb of the right-hand point in the direction of electric current. The curled finger gives the direction of the magnetic field.

Hence, the thumb shows the electric current.                            

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Does kinetic energy stay the same at all heights? pls help I have 12 minutes to finish the project and the teacher won't help me
Alex Ar [27]

Answer:

Kinetic energy does not stay the same at all heights

Explanation:

Well as the height and wind increase so does the kinetic energy it's like when you fall as you are about to hit the floor you speed increases

HOPE THIS HELPS YA :)

7 0
3 years ago
Explain why 15yr old need more calcium than adults
Tom [10]

Answer:

When adolescents get enough calcium during the teen years, they can start out their adult lives with the strong bones and significantly reduce their risk for fractures as an adult. Inadequate calcium intake during adolescence and young adulthood puts individuals at risk for developing osteoporosis later in life.

8 0
3 years ago
Read 2 more answers
2. An optical fibre is 1200km long and it takes light 0.006s to travel from one end to the other. Calculate the speed of light i
natita [175]
The average speed <em>appears to be</em> (distance) / (time) =

(length of the cable) / (time from when a pulse goes in until it comes out the other end) .

That's  1,200,000 meters/ 0.006 second  =  2 x 10^8 = <em>2 hundred million m/sec</em>

That figure is about 66.7% of the speed of light in vacuum.

The reason I went through all of this detail was to point out that this is
NOT necessarily the speed of light in this glass, for two reasons.

1).  The path of light through an optical fiber is not straight down the middle.  In the original fibers of 20 or 30 years ago, the light bounced back and forth off the inside walls of the fiber, and zig-zagged its way along the length.  In current modern fibers, it still zig-zags, but it's a more gentle, up-and-down curved path.  In either case, the distance covered by the light inside the fiber is more than the straight length of the cable, and the time it takes it to come out the other end is more than its actual speed inside the glass would have meant if it could have traveled straight through the pipe.

2).  This problem talks about an optical fiber that's 1,200km long.  There is loss in optical fiber, and you're NOT going to get light all the way through a single piece of it that's something like 745 miles long.  It takes electronic repeaters, "boosters", and regenerators every few miles to keep it going, and these devices add "latency" or time delay in the process of going through them.  That delay in the electronics shows up as apparent delay through the fiber-optic cable, and it makes the speed through the glass appear to be slower than it actually is.
6 0
3 years ago
Read 2 more answers
A student throws a set of keys vertically upward to his fraternity brother, who is in a window 3.60 m above. The brother's outst
Contact [7]

Answer:

v_{i}=10.10 m/s

Explanation:

The equation of the position is:

y=y_{i}+v_{i}t-0.5gt^{2}

Where:

v(i) is the initial velocity

The initial position y(i) will be zero and the final position y = 3.60 m.

So, we just need to solve this equation for v(i).

v_{i}=\frac{y+0.5gt^{2}}{t}

v_{i}=\frac{3.6+0.5*9.81*1.6^{2}}{1.6}

v_{i}=10.10 m/s

Therefore, the initial velocity is 10.10 m/s upwards.

I hope it helps you!

5 0
3 years ago
An airplane starts from rest and accelerates at a constant 3.00 m/s2
katrin2010 [14]

Answer:600 m

Explanation:

6 0
3 years ago
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