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klemol [59]
3 years ago
15

If classes C1 and C2 both implement an interface Cint, which has a method whichIsIt, and if C1 c = new C1( ); is performed at on

e point of the program, then a later instruction c.whichIsIt( ); will invoke the whichIsIt method defined in C1.
a. True.
b, False.
Computers and Technology
1 answer:
Assoli18 [71]3 years ago
5 0

Answer:

FALSE

Explanation:

Because C1 and C2 implement the same interface, they both implement whichIsIt. The variable c is known as a polymorphic variable, meaning that it can change from being an C1 to a C2. So, the message c.whichIsIt( ); may invoke C1's whichIsIt or C2's whichIsIt. This can only be known at runtime.

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Which of the following statements is true of alert files?
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They are only generated by Wireshark.

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3 years ago
Which keyboard feature is a form feed character?
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Answer:

B

Explanation:

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5 0
3 years ago
There are two String variables, s1 and s2, that have already been declared and initialized. Write some code that exchanges their
Ivan

Answer:

//here is code in java.

import java.util.*;

class Solution

{

// main method of class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // declare an initialize first string variables

     String st1="hello";

     // declare an initialize first string variables

     String st2="world";

     // create another string variable

    String st3;

    // exchange the value of both string variables

    st3=st1;

    st1=st2;

    st2=st3;

    System.out.println("value of first String after exchange: "+st1);

    System.out.println("value of second String after exchange: "+st2);

   }catch(Exception ex){

       return;}

}

}

Explanation:

declare and initialize two string variables.Create another string variable "st3". first assign value of "st1" to "st3" after then value of "st2" to "st1" and then  assign value of "st3" to "st2". This will exchange the values of both the string.

Output:

value of first String after exchange: world

value of second String after exchange: hello

8 0
3 years ago
Read 2 more answers
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