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pickupchik [31]
3 years ago
11

Please someone help mee

Chemistry
1 answer:
Nikitich [7]3 years ago
8 0

Answer:

13.9kj/mol

Explanation:

h = 891 -(393.5 +2*241.8)=1768.1=13.9kj/mol

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Match the following items. 1. balance observation using "how much". 2. graduated cylinder primary unit of mass. 3. hypothesis pr
crimeas [40]

Answer:

1. balance observation using "how much" = 5. quantitative instrument

2. graduated cylinder = 4. quantitaive instrument of volume

3. hypothesis proposed explanation= 7. qualitative descriptive observation

4. unit of volume= L

6. kg = primary unit of mass

Explanation:

there seem to be some typo error in uploading question but still it was clear to answer.

4 0
3 years ago
How many significant figures are in the measurement 102,400 meters?
RideAnS [48]

Answer:

4

Explanation:

the zeros after 102,4 are not significant.

4 0
3 years ago
HELP PLEASE!
Maslowich
I think you don’t need the help anymore so can I just take these real quick ?
8 0
3 years ago
What mass of solid sodium formate (of MW 68.01) must be added to 150 mL of 0.42 mol/L formic acid (HCOOH) to make a buffer solu-
Sergio [31]

Answer:

We need 4.28 grams of sodium formate

Explanation:

<u>Step 1:</u> Data given

MW of sodium formate = 68.01 g/mol

Volume of 0.42 mol/L formic acid = 150 mL = 0.150 L

pH = 3.74

Ka = 0.00018

<u>Step 2:</u> Calculate [base)

3.74 = -log(0.00018) + log [base]/[acid]

0 = log [base]/[acid]

0 = log [base] / 0.42

10^0 = 1 = [base]/0.42 M

[base] = 0.42 M

<u>Step 3:</u> Calculate moles of sodium formate:

Moles sodium formate = molarity * volume

Moles of sodium formate = 0.42 M * 0.150 L = 0.063 moles

<u>Step 4:</u> Calculate mass of sodium formate:

Mass sodium formate = moles sodium formate * Molar mass sodium formate

Mass sodium formate = 0.063 mol * 68.01 g/mol

Mass sodium formate = 4.28 grams

We need 4.28 grams of sodium formate

4 0
3 years ago
A large natural gas storage tank is arranged so that the pressure is maintained at 2.20 atm. On a cold day in December when the
irakobra [83]

Answer:

V₂= 33581.4  ft³

Explanation:

Given data:

Initial temperature = -15 °C (-15+273 = 258 k)

Initial volume = 28500 ft³

Final temperature = 31 °C (31+273 = 304)

Final volume = ?

Solution:

According to the Charles's law

Temperature and volume are directly related to each other.

V₁/T₁ = V₂/T₂

V₂ = V₁×T₂ /T₁

V₂ = 28500 ft³ × 304 k / 258 k

V₂ = 8664000 ft³.k/ 258 k

V₂= 33581.4  ft³

5 0
4 years ago
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